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pinterestaddict15
 one year ago
Will give medal. The polynomial x 3 + 5x 2 57x 189 expresses the volume, in cubic inches, of a shipping box, and the width is (x+3) in. If the width of the box is 15 in., what are the other two dimensions? ( Hint: The height is greater than the depth.)
A.
height: 19 in.
depth: 5 in.
B.
height: 21 in.
depth: 5 in.
C.
height: 19 in.
depth: 7 in.
D.
height: 21 in.
depth: 7 in.
I got this question wrong on a quiz, I thought it was C, but it was wrong. Does anyone know the correct answer?
pinterestaddict15
 one year ago
Will give medal. The polynomial x 3 + 5x 2 57x 189 expresses the volume, in cubic inches, of a shipping box, and the width is (x+3) in. If the width of the box is 15 in., what are the other two dimensions? ( Hint: The height is greater than the depth.) A. height: 19 in. depth: 5 in. B. height: 21 in. depth: 5 in. C. height: 19 in. depth: 7 in. D. height: 21 in. depth: 7 in. I got this question wrong on a quiz, I thought it was C, but it was wrong. Does anyone know the correct answer?

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BAdhi
 one year ago
Best ResponseYou've already chosen the best response.1Answer is B. We should be able to express the volume as following \[x^3+5x^257x189 = (ax+b)(cx+d)(x+3)\] after finding values for a,b,c,d and substituting the value for x ( ie, its given that x+3 = 15) , you should get answer as B

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440481911438:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440482244866:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440483116366:dw
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