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anonymous

  • one year ago

A car passes a landmark on a highway traveling at a constant rate of 55 kilometers per hour. One hour later, a second car passes the same landmark traveling in the same direction at 63 kilometers per hour. How much time after the second car passes the landmark will it overtake the first car? Do not do any rounding.

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  1. anonymous
    • one year ago
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    Okay. First, think about what conditions mean that one car passes another...

  2. anonymous
    • one year ago
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    I don't understand?

  3. anonymous
    • one year ago
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    well their distance travelled after the landmark must be same right?

  4. anonymous
    • one year ago
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    Yes

  5. anonymous
    • one year ago
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    Okay so then consider that the distance is x, alright? Then you know their speeds and the time difference. The second car starts one hour later. So, whatever time in which they reach at that same point, value of t for second car is t-1 hrs. Now equate speed/time for both

  6. anonymous
    • one year ago
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    I don't know how to do that. D:

  7. anonymous
    • one year ago
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    I'm sorry, I really don't understand this. I need help.

  8. anonymous
    • one year ago
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    Refer to the attachment from Mathematica.

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  9. anonymous
    • one year ago
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    |dw:1440487713058:dw|

  10. anonymous
    • one year ago
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    following?

  11. anonymous
    • one year ago
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    Yes sir/ma'am

  12. anonymous
    • one year ago
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    Then, distance=speed*time, right? That would mean 55*t=63*(t-1)

  13. anonymous
    • one year ago
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    solve this for t!

  14. anonymous
    • one year ago
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    7.875?

  15. anonymous
    • one year ago
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    yeah, sorry but the question need t-1 right?

  16. anonymous
    • one year ago
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    I chose t to be time elapsed for first... so 6.875 will be the answer.

  17. anonymous
    • one year ago
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    Oh, I understand now! Thanks. I have 5 more questions like this to do and I think I can get them on my own now. :)

  18. Jhannybean
    • one year ago
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    shouldn't it be `t+1` since it was an hour later?

  19. Jhannybean
    • one year ago
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    `t-1` would mean the second car left an hour before the first, no?

  20. anonymous
    • one year ago
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    I chose the other value for t for the question @Jhannybean. and no an hour late would mean lesser time elapsed right?.

  21. anonymous
    • one year ago
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    t represents time elapsed after crossing the landmark.

  22. Jhannybean
    • one year ago
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    time it takes for the first car to pass the landmark = t time it takes for the second car to pass the landmark an hour later = t+1

  23. anonymous
    • one year ago
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    Let t be the time to catch the first car. 55 (1 + t) = 63 t // Solve t = 55/8 = 6.875

  24. anonymous
    • one year ago
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    Thank you for the medal.

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