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anonymous

  • one year ago

How to find (a) & (b)

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    |dw:1440494083820:dw|

  3. anonymous
    • one year ago
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    In the figure, O is the centre of sector OAD, OC intersects BD at E such that ED=EO and AB = BC find (a) angle AOC, (b) Arc AC:CD

  4. anonymous
    • one year ago
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    yeah ...workin it out

  5. amilapsn
    • one year ago
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    This would help: |dw:1440496797254:dw|

  6. anonymous
    • one year ago
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    got it...are u here?

  7. phi
    • one year ago
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    there are probably a few ways. Here is one (not necessarily the best) |dw:1440509331827:dw|

  8. phi
    • one year ago
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    angle y plus 2x is 180 (sum of three angles in an isosceles triangle) thus y= 180-2x x+z form a 90 degree angle AOD. so x= 90-z this makes y= 180-2x = 180-180+2z and y= 2z next, we use angle y is the average of the intercepted arcs AC and C' D y= (CF + C'D)/2 arc CF= 1/2 central angle z, so CF= z/2 arc C' D = 90 + z thus we can say \[ y = \frac{(CF+C'D)}{2} \\ 2z\cdot 2 = CF+C'D \\ 4z = \frac{z}{2} + 90+z \] solve for z, to get z=36 degrees that means arc AC = 36 and arc CD= 90-36= 54 and their ratio is 2/3

  9. amilapsn
    • one year ago
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    Another way: |dw:1440564163627:dw|

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