anonymous
  • anonymous
How to find (a) & (b)
Mathematics
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anonymous
  • anonymous
How to find (a) & (b)
Mathematics
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
anonymous
  • anonymous
|dw:1440494083820:dw|
anonymous
  • anonymous
In the figure, O is the centre of sector OAD, OC intersects BD at E such that ED=EO and AB = BC find (a) angle AOC, (b) Arc AC:CD

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anonymous
  • anonymous
yeah ...workin it out
amilapsn
  • amilapsn
This would help: |dw:1440496797254:dw|
anonymous
  • anonymous
got it...are u here?
phi
  • phi
there are probably a few ways. Here is one (not necessarily the best) |dw:1440509331827:dw|
phi
  • phi
angle y plus 2x is 180 (sum of three angles in an isosceles triangle) thus y= 180-2x x+z form a 90 degree angle AOD. so x= 90-z this makes y= 180-2x = 180-180+2z and y= 2z next, we use angle y is the average of the intercepted arcs AC and C' D y= (CF + C'D)/2 arc CF= 1/2 central angle z, so CF= z/2 arc C' D = 90 + z thus we can say \[ y = \frac{(CF+C'D)}{2} \\ 2z\cdot 2 = CF+C'D \\ 4z = \frac{z}{2} + 90+z \] solve for z, to get z=36 degrees that means arc AC = 36 and arc CD= 90-36= 54 and their ratio is 2/3
amilapsn
  • amilapsn
Another way: |dw:1440564163627:dw|

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