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anonymous

  • one year ago

Write the equation of the line that passes through (–1, 5) and has a slope of 3 in point-slope form. x + 1 = 3(y – 5) x – 5 = 3(y + 1) y – 5 = 3(x + 1) y + 1 = 3(x – 5)

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  1. anonymous
    • one year ago
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    i forget the equation for point-slope form

  2. pooja195
    • one year ago
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    y-y1=m(x-x1) m=slope (x,y)

  3. Abhisar
    • one year ago
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    \(\sf Y=mX +C\)

  4. Sheraz12345
    • one year ago
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    y-y1=m(x-x1)

  5. anonymous
    • one year ago
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    so i have to use all of them?

  6. pooja195
    • one year ago
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    @abhisat they want point slope

  7. pooja195
    • one year ago
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    motown use wat i wrote

  8. anonymous
    • one year ago
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    i mean

  9. anonymous
    • one year ago
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    now that you wrote the equation its kind of self exploratory because y-(-1)=+1 which only one answer has

  10. LynFran
    • one year ago
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    |dw:1440513305569:dw|

  11. anonymous
    • one year ago
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    so with that format it would be y-5=3(x+1)

  12. LynFran
    • one year ago
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    yep

  13. anonymous
    • one year ago
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    ty

  14. LynFran
    • one year ago
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    welcome

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spraguer (Moderator)
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