raiders88
  • raiders88
need help
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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raiders88
  • raiders88
ok i need help on 5 problems
anonymous
  • anonymous
what are the problems
raiders88
  • raiders88
solve the equation : 4x--36

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More answers

misty1212
  • misty1212
HI!!
raiders88
  • raiders88
hi misty
misty1212
  • misty1212
\[4x-36\] is not an equation, because there is no equal sign there right?
raiders88
  • raiders88
oh wait srry yea it is
misty1212
  • misty1212
and equation would be something like \(4x-36=12\)
raiders88
  • raiders88
its 4x=-36
misty1212
  • misty1212
oooh
anonymous
  • anonymous
i see what you are saying misty
misty1212
  • misty1212
that you can solve by dividing \(-36\) by \(4\)
raiders88
  • raiders88
-9
misty1212
  • misty1212
if four times your number is \(-36\) then your number is \(-\frac{36}{4}\)
anonymous
  • anonymous
yes
misty1212
  • misty1212
yeah right
raiders88
  • raiders88
ok next one
misty1212
  • misty1212
lol
raiders88
  • raiders88
solve the following equation: 5x-15=50
misty1212
  • misty1212
this one takes two steps a) add 15 then b) divide by 5
raiders88
  • raiders88
where do i add 15
misty1212
  • misty1212
to both sides
raiders88
  • raiders88
15 and 50?
misty1212
  • misty1212
that gets rid of the \(-15\) on the left
misty1212
  • misty1212
yeah what is \(50+15\)?
raiders88
  • raiders88
65
misty1212
  • misty1212
ok so if \[5x-15=50\] then you know \[5x=65\]
misty1212
  • misty1212
divide by 5 to get your answer
anonymous
  • anonymous
you are really good at this misty i can do it but not that good
misty1212
  • misty1212
(blush)
raiders88
  • raiders88
13
raiders88
  • raiders88
yeah ur amazing misty i could kiss you
misty1212
  • misty1212
\[\color\magenta\heartsuit\]
anonymous
  • anonymous
<3
raiders88
  • raiders88
<3 <3
raiders88
  • raiders88
4(x+2)-17=35
misty1212
  • misty1212
ooh now it is going to take more steps lets get rid of the \(-17\)first by adding \(17\) to both sides what do you get?
raiders88
  • raiders88
17 and 35?
misty1212
  • misty1212
yes
raiders88
  • raiders88
ok
raiders88
  • raiders88
52
misty1212
  • misty1212
so if \[4(x+2)-17=35\] you know \[4(x+2)=52\]
misty1212
  • misty1212
now divide both sides by 4
raiders88
  • raiders88
4 and 50?
misty1212
  • misty1212
divide 52 by 4
raiders88
  • raiders88
13
misty1212
  • misty1212
ok so if \[4(x+2)=52\] you have \[x+2=13\] subtract 2 to get x
raiders88
  • raiders88
11
misty1212
  • misty1212
bingo
raiders88
  • raiders88
ok
misty1212
  • misty1212
want to check it?
raiders88
  • raiders88
nope
misty1212
  • misty1212
sounds good
raiders88
  • raiders88
ok um 2 more
misty1212
  • misty1212
lol
raiders88
  • raiders88
6x+12=4x-18
misty1212
  • misty1212
a) subtract \(4x\) from both sides you need the x's on one side of the equal sign
raiders88
  • raiders88
14
misty1212
  • misty1212
oh no \[6x+12=4x-18\] what is \(6x-4x\)?
raiders88
  • raiders88
2x
misty1212
  • misty1212
right, so we are at \[2x+12=-18\]
misty1212
  • misty1212
now subtract \(12\) from both sides
raiders88
  • raiders88
12 and 2?
misty1212
  • misty1212
\[2x+12=-18\\ 2x+12-12=-18-12\\ 2x=-18-12\] your job is to compute \(-18-12\)

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