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anonymous

  • one year ago

Let f(x) = -4x + 7 and g(x) = 10x - 6. Find f(g(x)).

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  1. Nnesha
    • one year ago
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    \[\huge\rm f(\color{red}{g(x)})\textrm {is same as }f(\color{reD}{10x-6})\] so substitute x for 10x-6 into f(x) function

  2. anonymous
    • one year ago
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    so it would be x = 3/5?

  3. Nnesha
    • one year ago
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    no f(g(x)) means you should substitute x for g(x) function which is 10x-6 so in other words replace x by 10x-6 x=10x-6

  4. anonymous
    • one year ago
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    ohh okay

  5. Nnesha
    • one year ago
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    \[\huge\rm f(\color{reD}{10x-6})=-4\color{reD}{x}+7\] replace the x by 10x-6

  6. anonymous
    • one year ago
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    wait i'm still confused

  7. Nnesha
    • one year ago
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    okay say it:=)

  8. Nnesha
    • one year ago
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    so what's ur question ?

  9. anonymous
    • one year ago
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    i don't get what you do after replacing the x with 10x-6

  10. Nnesha
    • one year ago
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    ohh distribute parentheses by 6

  11. Nnesha
    • one year ago
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    \[\huge\rm f(\color{reD}{10x-6})=-4\color{reD}{(10x-6)}+7\] distribute parentheses by 4 and then combine `like` terms

  12. anonymous
    • one year ago
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    so then f = -4(20x - 12) + 7 ??

  13. Nnesha
    • one year ago
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    hmm no

  14. Nnesha
    • one year ago
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    multiply both terms in the parentheses by outside number \[\huge\rm a(b+c)=a \times b+a \times c\] like this

  15. Nnesha
    • one year ago
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    |dw:1440514753158:dw|

  16. anonymous
    • one year ago
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    OHH so it's -40x + 24

  17. Nnesha
    • one year ago
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    \[\huge\rm \color{reD}{-4(10x-6)}+7\] \[\huge\rm \color{reD}{-40x+24}+7\] red part equal to -4x+24 right now combine like terms

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