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anonymous
 one year ago
Describe the vertical asymptote(s) and hole(s) for the graph of y= (x+3)(x+4) / (x+4)(x+2).
Answers:
a) asymptote: x=3 and hole: x=2
b) asymptote: x=2 and hole: x= 4
c) asymptote: x=2 and hole: x=4
d) asymptote: x=2 and hole: x=4
anonymous
 one year ago
Describe the vertical asymptote(s) and hole(s) for the graph of y= (x+3)(x+4) / (x+4)(x+2). Answers: a) asymptote: x=3 and hole: x=2 b) asymptote: x=2 and hole: x= 4 c) asymptote: x=2 and hole: x=4 d) asymptote: x=2 and hole: x=4

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@nincompoop @Hero please help me

Hayleymeyer
 one year ago
Best ResponseYou've already chosen the best response.0cross off what you Dont think is the answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I WILL FAN + MEDAL PLEASE HELP !

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2for \(\color{green}{\rm Vertical~ asy.}\) set the denominator equal to zero and then solve for the variable. for\(\color{green}{\rm Horizontal ~asy.}\) focus on highest degrees ~if the highest degree of the numerator is greater than the denominator then `No horizontal asy.` \[\color{reD}{\rm N}>\color{blue}{\rm D}\] example \[\large\rm \frac{ 7x^\color{ReD}{3} +1}{ 4x^\color{blue}{2}+3 }\] ~if the highest degree of the denominator is greater than the highest degree of the numerator then `y=0` would be horizontal asy. \[\rm \color{reD}{N}<\color{blue}{\rm D}\] example:\[\large\rm \frac{ 7x^\color{red}{2}+1 }{ 4x^\color{blue}{3}+3 }\] ~if both degrees are the same then divide the leading coefficient of the numerator by the leading coefficient of the denominator \[\rm \color{red}{N}=\color{blue}{D}\] \[\large\rm \frac{ 8x^\color{reD}{3}+1 }{ 4x^\color{blue}{3}+3 }\] \[\rm \frac{ 8x^3 }{ 4x^3 } =2\] horizontal asy. =2

hick4life
 one year ago
Best ResponseYou've already chosen the best response.0ok lets see what we got here

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i will medal and fan if you get me the answer @hick4life

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[\rm f(x)=\frac{ (x+3)(x+4)}{ (x+2)(x+4)}\] first simplify is there anything you can cacnel out?

hick4life
 one year ago
Best ResponseYou've already chosen the best response.0Do we have a graph line

dumbcow
 one year ago
Best ResponseYou've already chosen the best response.0@jordanaz26 , just getting the answer wont help you on the next question...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah we can cancel out (x+4) @Nnesha

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yes right! so \[f(x)=\frac{ (x+3) }{ x+2}\]set the denominator equal to zero to find vertical asy

hick4life
 one year ago
Best ResponseYou've already chosen the best response.0Go ahead and cancel (4x+)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2:=) looks good wait a sec plz

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sure ! so we got the vertical asymptote which is x:2, but it also asks for the hole(s) @Nnesha

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yeah i'mm trying to find hole in my notebook i forgot how to find it

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2ahh okay what are the factors that in common to both numerator and denominator ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0of 3 and 2 ? @Nnesha

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2common factors would be hole \[\rm f(x)=\frac{ (x+3)\color{reD}{(x+4)}}{ (x+2)\color{red}{(x+4)}}\] in this question x+4 is common right so set it equal to zero x+4=0 solve for x that value would be hole

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh !!! so its x=4 ! thank you so much ! fan and medal ! @Nnesha
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