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anonymous
 one year ago
Let h(x) = kx+5, domain of f(x) is [5,7]
, domain of f(h(x)) is [6,1] and range of h(x) is the same as the domain f(x), then the value of k is
anonymous
 one year ago
Let h(x) = kx+5, domain of f(x) is [5,7] , domain of f(h(x)) is [6,1] and range of h(x) is the same as the domain f(x), then the value of k is

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ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1is the answer \(k\in [\frac{1}{3},~~2]\) ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its an mcq and options are 1/3 4/5 1 none

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and its a single correct

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1`domain of f(h(x)) is [6,1] ` dw:1440520009960:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1`domain of f(x) is [5,7]` therefore we must have : `5 < h(x) < 7` does that look fine so far ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1h(x) is absolute value function, so we don't need to wry about the lower bound 5

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1we just need to make sure that h(x) is not greater than 7 in the interval [6, 1]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1because f(x) becomes undefined for values greater than 7 dw:1440520422396:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what if we try to draw the graph of h(x) with the vertex 5/k and y intercept (0,5) and draw two legs of the mod function and try to forcefully get the coordinates (1,7) from one part and from other ( 6,7) and take their intersection?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I am still getting a range.. wbu?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1same http://www.wolframalpha.com/input/?i=solve+%7C6k%2B5%7C+%3C+7%2C+%7Ck%2B5%7C%3C7
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