Let h(x) = |kx+5|, domain of f(x) is [-5,7]
, domain of f(h(x)) is [-6,1] and range of h(x) is the same as the domain f(x), then the value of k is
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and its a single correct
`domain of f(h(x)) is [-6,1] `
`domain of f(x) is [-5,7]`
therefore we must have : `-5 < h(x) < 7`
does that look fine so far ?
h(x) is absolute value function, so we don't need to wry about the lower bound -5
we just need to make sure that h(x) is not greater than 7 in the interval [-6, 1]
because f(x) becomes undefined for values greater than 7
what if we try to draw the graph of h(x) with the vertex -5/k and y intercept (0,5) and draw two legs of the mod function and try to forcefully get the coordinates (1,7) from one part and from other ( -6,7) and take their intersection?
I am still getting a range.. wbu?