A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

mathmath333

  • one year ago

Probablity question

  • This Question is Closed
  1. mathmath333
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \(\large \color{black}{\begin{align} & \normalsize \text{India plays two matches each with New Zealand and South Africa.} \hspace{.33em}\\~\\ & \normalsize \text{ In any match , the probability of different outcomes for India} \hspace{.33em}\\~\\ & \normalsize \text{ is given below -} \hspace{.33em}\\~\\~\\~\\ & \begin{array}{|c|c|c|} \hline \text{Outcome} & \text{Win} & \text{Loss} & \text{Draw} \\ \hline \text{Probablity} & 0.5 & 0.45 & 0.05 \\ \hline \text{Points} & 2 & 0 & 1 \\ \hline \end{array} & \hspace{.33em}\\~\\ & \normalsize \text{1.) What is the probablity india getting atleast 7 points .} \hspace{.33em}\\~\\ & \normalsize \text{in the contest ? assume south africa and newzealand } \hspace{.33em}\\~\\ & \normalsize \text{play 2 matches. } \hspace{.33em}\\~\\ & \normalsize \text{2.) What is the probablity Soth africa getting atleast 4 points .} \hspace{.33em}\\~\\ & \normalsize \text{ assume south africa and newzealand play 2 matches. } \hspace{.33em}\\~\\ \end{align}}\)

  2. dumbcow
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    you have to do it case by case prob(8pts) = (.5)^4 because they have to win all 4 games prob(7pts) = 4*(.5)^3 *.05 because you have to win 3 and tie 1 (there are 4 ways this could happen) to find "at least 7 pts", you must add up prob(7) + prob(8)

  3. mathmath333
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    how come this prob(8pts) = (.5)^4

  4. dumbcow
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    there is .5 chance of winning each match, each match is independent event, so multiply probabilites .5*.5*.5*.5 = (.5)^4

  5. mathmath333
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok then here where \(\color{red}{4}\) comes from prob(7pts) = \(\color{red}{4}\)*(.5)^3 *.05

  6. mathmath333
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok there are 4 ways to have 2221 1222 2122 2212 is it this ?

  7. dumbcow
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    correct

  8. dumbcow
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    for part 2, there are more cases you need to find p(4), p(5), p(6), p(7), p(8) and add them all up

  9. dumbcow
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    actually it may be easier to find p(0), p(1), p(2), p(3) then subtract there total from 1 \[P(x \ge 4) = 1 - P(x<4)\]

  10. mathmath333
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thanks

  11. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.