anonymous
  • anonymous
Write the equation of a line with a slope of 3 and a y-intercept of 1. y = x + 3 y = 3x + 1 3x + y = 1 <-- I picked this. Am I right? x + 3y = 1
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
anonymous
  • anonymous
It had a slope of -1 but that is the closest out of them all.
pooja195
  • pooja195
y=mx+b m=slope b=y-intercept

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anonymous
  • anonymous
Ah! It must be B than
anonymous
  • anonymous
Then*
pooja195
  • pooja195
yes :)
anonymous
  • anonymous
i have one more!
anonymous
  • anonymous
Should I close this one and tag you in the new one?
pooja195
  • pooja195
just post it here
anonymous
  • anonymous
Write the equation of the line that passes through (1, 5) and (–2, 14) in slope-intercept form. y = 3x + 2 y = 3x + 8 y = –3x – 2 y = –3x + 8
pooja195
  • pooja195
\[\LARGE \frac{y_2-y_1}{x_2-x_1}=slope\] find the slope first
anonymous
  • anonymous
ok, of one of them right?
pooja195
  • pooja195
Find the slope only first
pooja195
  • pooja195
@Nnesha can u finish plz gotta go
anonymous
  • anonymous
y = 3x + 2 has a slope of 3 y = 3x + 8 has a slope of 3
anonymous
  • anonymous
doing the next two one sec
anonymous
  • anonymous
y = -3x - 2 has a slope of -3
Nnesha
  • Nnesha
use the formula she gave u plugin the x''s and y's values to find slope (1, 5) and (–2, 14)
anonymous
  • anonymous
yeah I am. Check the other slopes I already gave out
Nnesha
  • Nnesha
no we need to find slopes we don't know if it's -3 or positive 3 that's why we should use that formula to find out
Nnesha
  • Nnesha
\[\LARGE\rm \frac{y_2-y_1}{x_2-x_1}=slope\] \[\huge\rm (x_1,y_1)(x_2 ,y_2)\] \[\huge\rm (1,5)(-2,14)\] x_1 = first x x_2 2nd x

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