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anonymous

  • one year ago

Write the equation of a line with a slope of 3 and a y-intercept of 1. y = x + 3 y = 3x + 1 3x + y = 1 <-- I picked this. Am I right? x + 3y = 1

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  1. anonymous
    • one year ago
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    @pooja195

  2. anonymous
    • one year ago
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    It had a slope of -1 but that is the closest out of them all.

  3. pooja195
    • one year ago
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    y=mx+b m=slope b=y-intercept

  4. anonymous
    • one year ago
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    Ah! It must be B than

  5. anonymous
    • one year ago
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    Then*

  6. pooja195
    • one year ago
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    yes :)

  7. anonymous
    • one year ago
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    i have one more!

  8. anonymous
    • one year ago
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    Should I close this one and tag you in the new one?

  9. pooja195
    • one year ago
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    just post it here

  10. anonymous
    • one year ago
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    Write the equation of the line that passes through (1, 5) and (–2, 14) in slope-intercept form. y = 3x + 2 y = 3x + 8 y = –3x – 2 y = –3x + 8

  11. pooja195
    • one year ago
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    \[\LARGE \frac{y_2-y_1}{x_2-x_1}=slope\] find the slope first

  12. anonymous
    • one year ago
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    ok, of one of them right?

  13. pooja195
    • one year ago
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    Find the slope only first

  14. pooja195
    • one year ago
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    @Nnesha can u finish plz gotta go

  15. anonymous
    • one year ago
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    y = 3x + 2 has a slope of 3 y = 3x + 8 has a slope of 3

  16. anonymous
    • one year ago
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    doing the next two one sec

  17. anonymous
    • one year ago
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    y = -3x - 2 has a slope of -3

  18. Nnesha
    • one year ago
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    use the formula she gave u plugin the x''s and y's values to find slope (1, 5) and (–2, 14)

  19. anonymous
    • one year ago
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    yeah I am. Check the other slopes I already gave out

  20. Nnesha
    • one year ago
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    no we need to find slopes we don't know if it's -3 or positive 3 that's why we should use that formula to find out

  21. Nnesha
    • one year ago
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    \[\LARGE\rm \frac{y_2-y_1}{x_2-x_1}=slope\] \[\huge\rm (x_1,y_1)(x_2 ,y_2)\] \[\huge\rm (1,5)(-2,14)\] x_1 = first x x_2 2nd x

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