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do you know pythagorean thm ?
Yea, for the most part.

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ok |dw:1440520824213:dw|
So I tried subtracting 9^2 by 5^2 and got 56.. I'm not sure what I've done wrong...
no thats right ... 81-25 = 56 now you have to take sqrt to solve for x \[x^2 = 56\] \[x = \sqrt{56}\]
I got 7.5 and it's not an option...
right be careful, notice the answer choices leave as radical not decimal also we want Area, so we are not done \[Area = 5*x = 5 \sqrt{56}\]
can you simplify the radical by factoring out a perfect square
No. I have no clue what that even means o.o (I'm sorry I'm so horrible at this >.<)
thats ok the goal is to get the number inside the radical(sqrt) as small as possible the only way to get rid of sprt is by having a perfect square .... 4,9,16,25... example: \[\sqrt{9} = \sqrt{3^2} = 3\] also you can split up a sqrt into smaller factors example: \[\sqrt{45} = \sqrt{9*5} = \sqrt{9} \sqrt{5} = 3 \sqrt{5}\] notice once you break it into sqrt9 and sqrt5 , you can get rid of sqrt9 because it equals 3
so how do I do that with 56... I don't understand
split it up ... like 45 has factors 9 and 5 what are factors of 56 .... try dividing by 4,9,16,25 etc
1,2,4,7,8,14,28,56,
yes look for perfect squares.... the only one is 4 4 pairs with 14 \[\sqrt{56} = \sqrt{4*14} = \sqrt{4} \sqrt{14}\]
..so my answer would be 14?
no dont try to jump ahead and just match a number to one of the answer choices we want AREA of rectangle with sides 5 and sqrt(56) we factored 56 into 4 and 14 \[\sqrt{56} = \sqrt{4} \sqrt{14} = 2 \sqrt{14}\] Last multiply the 2 sides of rectangle to get AREA \[Area = 5 * \sqrt{56} = 5 * 2 \sqrt{14} = 10 \sqrt{14}\]
Oh, okay. I think I get it now. Thanks.
yw keep working on simplifying radicals
gotta go :)
Ok have a good day

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