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anonymous

  • one year ago

Find the LCD that would eliminate the fractions in this equation x/2+1/4=3/4

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  1. bradely
    • one year ago
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    x/2+1/4=3/4 Subtract 1/4 from each side x/2+1/4-1/4=3/4-1/4 x/2 =3/4-1/4 x/2 =(3-1)/4 x/2 =2/4 x =1 Source: http://www.mathskey.com/question2answer/

  2. mathstudent55
    • one year ago
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    The denominators are 2, 4, and 4. What is the smallest number that you can divide evenly by 2 and 4?

  3. anonymous
    • one year ago
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    \[\frac{ x }{ 2 } + \frac{ 1 }{ 4 } = \frac{ 3 }{ 4 }\]

  4. mathstudent55
    • one year ago
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    @bradely If this were a question on a test, you'd get no credit for it because even though you solved the equation correctly, you didn't answer the question being asked.

  5. anonymous
    • one year ago
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    I already tried to put in 1 but it says its wrong. I don't understand how I'm getting it wrong.

  6. mathstudent55
    • one year ago
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    Here is an example. Let's use the number 16 as a common denominator. 16/2 = 8 (no remainder) 16/4 = 4 (no remainder) 16 is a common denominator for 2 and 4 because when you divide 16 by 2 or by 4 you get no remainder. 16 is not the least common denominator. This problem is asking for the least common denominator (LCD) of 2 and 4. What is the smallest number that you can divide by 2 and divide by 4 and get no remainder? That is what an LCD is.

  7. anonymous
    • one year ago
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    2, 4, and 4. Which is the smallest number?

  8. mathstudent55
    • one year ago
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    One way to find the least common denominator of numbers is to list the multiples of the numbers. Take each number, and multiply it by 2, 3, 4, 5, 6, ... Write those multiples. Then look for the smallest multiple that is common to both.

  9. mathstudent55
    • one year ago
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    Here is an example. Find the LCD of 3 and 5. Solution Multiples of 3: 3, 6, 9, 12, 15, 18, 21, ... Multiples of 5: 5, 10, 15, 20, 25, ... Smallest multiple of both 3 and 5: 15 15 is the LCD of 3 and 5 Now do the same for 2 and 4.

  10. triciaal
    • one year ago
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    @kspencer you did not answer the question asked. read the question again then follow what @mathstudent55 has above

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