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anonymous

  • one year ago

I will give medal! 12(20 − 17) − 3 ∙ 6 i need someone to help me understand.

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  1. anonymous
    • one year ago
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    Do you know PEMDAS?

  2. anonymous
    • one year ago
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    what?

  3. anonymous
    • one year ago
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    Please excuse my dear aunt sally?

  4. anonymous
    • one year ago
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    ooh ya

  5. anonymous
    • one year ago
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    P Paratheses E Exponets M Multiplication D Division A Addition S Subtraction All multiplication and division from left to right All addition and subtraction from left to right also.

  6. anonymous
    • one year ago
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    ok

  7. anonymous
    • one year ago
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    Do you know how to solve the problem?;o

  8. anonymous
    • one year ago
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    mmm

  9. anonymous
    • one year ago
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    im not getting it still

  10. anonymous
    • one year ago
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    12(20 − 17) − 3 ∙ 6 P Paratheses E Exponets M Multiplication D Division A Addition S Subtraction Step 1 Paratheses - (20 - 17) = ?

  11. anonymous
    • one year ago
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    3

  12. anonymous
    • one year ago
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    12(20 − 17) − 3 ∙ 6 P Paratheses E Exponets M Multiplication D Division A Addition S Subtraction Step 1 Paratheses - (20 - 17) = 3 Between 12(20 always add a multiplication sigh like " 12 x (20

  13. anonymous
    • one year ago
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    12(20 − 17) − 3 ∙ 6 P Paratheses E Exponets M Multiplication D Division A Addition S Subtraction Step 1 Paratheses - (20 - 17) = ?

  14. anonymous
    • one year ago
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    12(20 − 17) − 3 ∙ 6 P Paratheses E Exponets M Multiplication D Division A Addition S Subtraction Step 1 Paratheses - (20 - 17) = ?

  15. anonymous
    • one year ago
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    ooh i remember so you always start with the ( ) i remember this in 6 grade when i was in school

  16. anonymous
    • one year ago
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    Its okay im in 7th grade xD

  17. anonymous
    • one year ago
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    lol you probably would be shocked but im in 9 and trying to get in my right grade which is 10th

  18. anonymous
    • one year ago
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    so its 18

  19. anonymous
    • one year ago
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    You got it!!! and its okay xD School sucks

  20. anonymous
    • one year ago
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    ya alot thanks :)

  21. anonymous
    • one year ago
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    Tag me if you need anymore help @Pizzalover123

  22. anonymous
    • one year ago
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    Your welcome xD Anytime

  23. anonymous
    • one year ago
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    oki

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spraguer (Moderator)
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