## zmudz one year ago Find $$\max(A,B,C,D)$$ in the partial fractions expansion of $$12\frac{x^3+4}{(x^2-1)(x^2+3x+2)} = \frac{A}{x-1} + \frac{B}{x+2} + \frac{C}{x+1} + \frac{D}{(x+1)^2}.$$

1. IrishBoy123

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2. freckles

You can find A,B,C,D by combining the fractions on the right and then comparing the numerators on both sides to actually find A,B,C, and D

3. freckles

I used heaviside method plugged in x=-2,-1,1,0