wolfmegan2612
  • wolfmegan2612
I need help on order of operations
Mathematics
chestercat
  • chestercat
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wolfmegan2612
  • wolfmegan2612
-12/3*(-8+(-4)^2-6)+2
mathstudent55
  • mathstudent55
\(-12 \div 3 \times [-8+(-4)^2-6]+2\) Start with the innermost parentheses: \(= -12 \div 3 \times [-8+\color{red}{(-4)^2}-6]+2\) \(= -12 \div 3 \times [-8+\color{red}{16}-6]+2\) The brackets now become parentheses, so work inside the parentheses. \(= -12 \div 3 \times \color{green}{(-8+16-6)}+2\) Inside the parentheses, do additions and subtractions in the order they appear from left to right. \(= -12 \div 3 \times \color{green}{(-8+16-6)}+2\) \(= -12 \div 3 \times \color{green}{(8-6)}+2\) \(= -12 \div 3 \times \color{green}{2}+2\) Now work on multiplications and divisions in the order they appear from left to right. \(= \color{blue}{-12 \div 3 \times 2}+2\) \(= \color{blue}{-4 \times 2}+2\) \(= \color{blue}{-8}+2\) \(= -8+2\) Finally, there is only one addition left to do. \(= - 6\)

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