## anonymous one year ago I need help on order of operations

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1. anonymous

-12/3*(-8+(-4)^2-6)+2

2. mathstudent55

$$-12 \div 3 \times [-8+(-4)^2-6]+2$$ Start with the innermost parentheses: $$= -12 \div 3 \times [-8+\color{red}{(-4)^2}-6]+2$$ $$= -12 \div 3 \times [-8+\color{red}{16}-6]+2$$ The brackets now become parentheses, so work inside the parentheses. $$= -12 \div 3 \times \color{green}{(-8+16-6)}+2$$ Inside the parentheses, do additions and subtractions in the order they appear from left to right. $$= -12 \div 3 \times \color{green}{(-8+16-6)}+2$$ $$= -12 \div 3 \times \color{green}{(8-6)}+2$$ $$= -12 \div 3 \times \color{green}{2}+2$$ Now work on multiplications and divisions in the order they appear from left to right. $$= \color{blue}{-12 \div 3 \times 2}+2$$ $$= \color{blue}{-4 \times 2}+2$$ $$= \color{blue}{-8}+2$$ $$= -8+2$$ Finally, there is only one addition left to do. $$= - 6$$