anonymous
  • anonymous
Point A (-4, 2) and Point B (2, 4) lie in the xy-coordinate plane. If point C lies in the first quadrant and contains the coordinates (p, q), where p < 2 and q < 4, which of the following could be the area of triangle ABC? (Can be more than one) a. 1.1 b. 3.9 c. 11.9
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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triciaal
  • triciaal
|dw:1440533539013:dw|
phi
  • phi
A is at (-4,2) QII
triciaal
  • triciaal
Area of a triangle is half base times perpendicular height

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More answers

triciaal
  • triciaal
sorry @ phi thanks
triciaal
  • triciaal
|dw:1440533830048:dw|
anonymous
  • anonymous
sorry bit confused
phi
  • phi
I changed my mine. we can get a size of 12 so all 3 points ?
triciaal
  • triciaal
|dw:1440533941559:dw|
anonymous
  • anonymous
so the hypotenuse would be 36 right?
anonymous
  • anonymous
oh wait nvm
phi
  • phi
|dw:1440534102758:dw|
anonymous
  • anonymous
how do we find c?
anonymous
  • anonymous
point c*
phi
  • phi
it seems to me if we move the third point closer to the line AB, we can make a triangle with as small an area as we want.
phi
  • phi
we can make a triangle with area 12 (see above) and we can move the point c a little closer , so that the area is 11.9 (off-hand, we don't know where, but we know it's possible) ditto for the other two choices.
anonymous
  • anonymous
where did you get 6/2 from?
anonymous
  • anonymous
hmmm nvm i think i got it
phi
  • phi
1/2 * base* height= area of triangle
anonymous
  • anonymous
|dw:1440534753143:dw|
anonymous
  • anonymous
does this work?
anonymous
  • anonymous
@phi @triciaal
triciaal
  • triciaal
c 11.9 yes
triciaal
  • triciaal
|dw:1440536164771:dw|
triciaal
  • triciaal
|dw:1440537086432:dw|
triciaal
  • triciaal
for some reason I think we should have 2 correct answers

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