anonymous
  • anonymous
solve this system of equation using either substitution or elimination method
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
\[x^{2}+y = 6\] \[x+y=4\]
tkhunny
  • tkhunny
Well, do it. The isolated 'y' in each is pretty compelling.
anonymous
  • anonymous
hey do you still need help? willing to walk you through it

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anonymous
  • anonymous
yes i neeed a walk through please lol
anonymous
  • anonymous
I would consider isolating y in each equation and then setting them equal to each other (not the y's the equation they are equal to) can you do that
anonymous
  • anonymous
|dw:1440534476791:dw|
anonymous
  • anonymous
like that? :s
anonymous
  • anonymous
perfect now set them equal so that y=y
anonymous
  • anonymous
what do you mean y=y?
anonymous
  • anonymous
set it: 4-x = 6-x^2
anonymous
  • anonymous
does that make sense why we would do that?
anonymous
  • anonymous
bc if they are both y then they equal each other
anonymous
  • anonymous
yes now we have to solve for x, it is going to turn into a quadratic function: 4-x = 6-x^2 -4 on both sides -x = 2-x^2 +x on both sides 2-x^2 + x = 0 Now order it correctly: -x^2 + x + 2 = 0 but -x^2 needs to be positive so switch all the signs: x^2 - x - 2 = 0 Making sense so far? Can you factor this?
anonymous
  • anonymous
so i factor it and get the x's and then i plug tose into the equation to get the y points of intersection?
anonymous
  • anonymous
yep!!
anonymous
  • anonymous
did I help?
anonymous
  • anonymous
let me know what you get please
anonymous
  • anonymous
hey @sarahg7 what did you end up getting...
anonymous
  • anonymous
@twistnflip i got (-1,5) and (2,2)
anonymous
  • anonymous
which method was that btw

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