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anonymous

  • one year ago

Use the formula for the sum of the first n terms of a geometric sequence to solve. Find the sum of the first 8 terms of the geometric sequence: -8, -16, -32, -64, -128, . . . . A. -2003 B. -2040 C. -2060 D. -2038

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  1. anonymous
    • one year ago
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    @Michele_Laino

  2. anonymous
    • one year ago
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    i thought it was b

  3. Michele_Laino
    • one year ago
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    the first term is: a1=-8, the constant is d=2 so the requested sum, is: \[\Large {S_8} = {a_1}\frac{{1 - {q^8}}}{{1 - q}} = - 8 \cdot \frac{{1 - 256}}{{1 - 2}} = ...?\]

  4. anonymous
    • one year ago
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    \[r=\frac{ -16 }{ -8 }=2\]

  5. anonymous
    • one year ago
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    i got the answer thnx for the help doe

  6. anonymous
    • one year ago
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    Find the probability. What is the probability that a card drawn from a deck of 52 cards is not a 10?

  7. anonymous
    • one year ago
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    i need help with this one though

  8. anonymous
    • one year ago
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    A. 12/13 B. 9/10 C. 1/13 D. 1/10 is my answers

  9. anonymous
    • one year ago
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    \[\frac{ C_{1}^{48} }{ C _{1}^{52} }=\frac{ 48 }{ 52 }=?\]

  10. anonymous
    • one year ago
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    im not sure

  11. anonymous
    • one year ago
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    @Nnesha @dan815

  12. anonymous
    • one year ago
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    @Mehek14

  13. anonymous
    • one year ago
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    it would be 1/13 right

  14. anonymous
    • one year ago
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    \[\frac{ 48 }{ 52 }=\frac{ 12 }{ 13 }\]

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