Use the formula for the sum of the first n terms of a geometric sequence to solve. Find the sum of the first 8 terms of the geometric sequence: -8, -16, -32, -64, -128, . . . . A. -2003 B. -2040 C. -2060 D. -2038

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Use the formula for the sum of the first n terms of a geometric sequence to solve. Find the sum of the first 8 terms of the geometric sequence: -8, -16, -32, -64, -128, . . . . A. -2003 B. -2040 C. -2060 D. -2038

Mathematics
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i thought it was b
the first term is: a1=-8, the constant is d=2 so the requested sum, is: \[\Large {S_8} = {a_1}\frac{{1 - {q^8}}}{{1 - q}} = - 8 \cdot \frac{{1 - 256}}{{1 - 2}} = ...?\]

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\[r=\frac{ -16 }{ -8 }=2\]
i got the answer thnx for the help doe
Find the probability. What is the probability that a card drawn from a deck of 52 cards is not a 10?
i need help with this one though
A. 12/13 B. 9/10 C. 1/13 D. 1/10 is my answers
\[\frac{ C_{1}^{48} }{ C _{1}^{52} }=\frac{ 48 }{ 52 }=?\]
im not sure
it would be 1/13 right
\[\frac{ 48 }{ 52 }=\frac{ 12 }{ 13 }\]

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