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ok here it is
also i have a few is that ok
I need to see it to see if i am able to help
Line M is represented by the following equation: x + y = −1 What is most likely the equation for line P so the set of equations has infinitely many solutions? 2x + 2y = 2 2x + 2y = 4 2x + 2y = −2 x − y = 1
also i only have 5 questions ok
i will give medal after
even if i get some wrong just because you helped me i will give medal at the end
hello are you still there
You want to find a line that is a parallel to the given line. Mechanically what we'll be doing is, Taking our line \(\large\rm x + y = −1 \) Adding each of the options to it, and seeing which one gives us a result of 0=0. Example: I'll add our line and the 4th option:|dw:1440538891099:dw|This gave us 2x=0 which will lead to a `unique solution` of x=0. This is a single solution.
So this is no bueno, we want infinitely many solutions, this only happens when both variables disappear in the operation.
so this is a single soulution
I'm saying that the "solution" or "intersection" of these two lines is at a single place, so it is clearly the wrong answer for us.
but thats not what we want we want infinate soulutions correct
yes, correct :)
ok got it
How bout we try the first one:|dw:1440539063251:dw|
We need the coefficients to match up, so what can we do to the first equation?
im not sure im realy bad at math do you think you can give me like a hint to understand how to find the coefficients
Let's just pay attention to the x's. I want the x's to disappear through some type of addition. I have 2x's in the bottom so I'm going to need 2x's in the top equation as well. So let's multiply the entire top equation by 2.
ok i think i understand were your going with this
|dw:1440539255066:dw|Gives us something like this, ya?
ok so we added the 2 right
and then mutyplye
We `multiplied` by 2! :O not added. I guess in this case, in order to make the x's disappear, we'll need to `subtract` the bottom equation, not add it.
|dw:1440539392434:dw|Careful though, you have to subtract everything.
So what dare you left with? Try to deal with each column. 2x - 2x?
would that make everything 0
2x - 2x = 0 2y - 2y = 0 The left side is clearly 0, good. -2 - 2 = ?
so then the answer would be 0
Noooo :O Check that last line again carefully!
ok so 0
lol im sorry im super confused
If you're at negative 2, and you take 2 away from that, you become even more negative.
wait would it be 4
Ok good! So we end up with this result: \(\large\rm 0=-4\) Which is `false`. Therefore the system containing these two lines has NO solution. So again, this is not the one we're looking for. Your princess is in another castle :o
ok lol so now on to the other aswer right
Let's check out the 3rd option: x + y = -1 2x + 2y = −2
also im sorry math is the only thing i realy suck at
so would we do the same thing we did last time
Yah, that seems like a good idea.
Again, we multiply by 2 to match up the x's. 2(x + y = -1) 2x + 2y = −2 Giving us: 2x + 2y = -2 2x + 2y = −2
And then do some subtraction or addition to combine them. What are we gonna get this time? :o
umm the end parts on both sides are nagative so those be 0s
Well notice that both equations are exactly the same now, ya? What happens when you subtract something from itself? You're gonna get 0. So good, in this case we end up with 0=0. So this system of two lines gives us infinitely many solutions!
so thats the answer
yay team \c:/ we got it!
also wich question was this
The only one that you asked :D lol I dunno, you didn't number it :d
no i mean the question to the question we just worked on is it x + y = -1 2x + 2y = −2
Line M was `given` to be x+y=-1. And our `answer` that we obtained for line P is the third one, 2x+2y=-2
ok cool next question! :)
Line Q is represented by the following equation: 2x + y = 11 Which equation completes the system that is satisfied by the solution (3, 5)? x + 2y = 15 x + y = 15 x + y = 8 x − y = 2
i think its B or A
I gotta go make some foods. If you need further help, close this and open up another thread. This one is getting too long and messy. You can use the @ symbol to page someone for help. Example @zepdrix The people at the top of the lobby are usually a bunch of smarty pants. Include your question in title, it will help to get it answered faster. Don't just call it "need help with math". Just a little tip :) I'll try to come by and help when I can :) But the belly is rumblin at the moment!