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anonymous
 one year ago
hello i need help in math can anyone help me.
anonymous
 one year ago
hello i need help in math can anyone help me.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0also i have a few is that ok

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I need to see it to see if i am able to help

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Line M is represented by the following equation: x + y = −1 What is most likely the equation for line P so the set of equations has infinitely many solutions? 2x + 2y = 2 2x + 2y = 4 2x + 2y = −2 x − y = 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0also i only have 5 questions ok

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i will give medal after

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0even if i get some wrong just because you helped me i will give medal at the end

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hello are you still there

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1You want to find a line that is a parallel to the given line. Mechanically what we'll be doing is, Taking our line \(\large\rm x + y = −1 \) Adding each of the options to it, and seeing which one gives us a result of 0=0. Example: I'll add our line and the 4th option:dw:1440538891099:dwThis gave us 2x=0 which will lead to a `unique solution` of x=0. This is a single solution.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1So this is no bueno, we want infinitely many solutions, this only happens when both variables disappear in the operation.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so this is a single soulution

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1I'm saying that the "solution" or "intersection" of these two lines is at a single place, so it is clearly the wrong answer for us.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but thats not what we want we want infinate soulutions correct

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1How bout we try the first one:dw:1440539063251:dw

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1We need the coefficients to match up, so what can we do to the first equation?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im not sure im realy bad at math do you think you can give me like a hint to understand how to find the coefficients

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Let's just pay attention to the x's. I want the x's to disappear through some type of addition. I have 2x's in the bottom so I'm going to need 2x's in the top equation as well. So let's multiply the entire top equation by 2.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok i think i understand were your going with this

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1dw:1440539255066:dwGives us something like this, ya?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so we added the 2 right

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1We `multiplied` by 2! :O not added. I guess in this case, in order to make the x's disappear, we'll need to `subtract` the bottom equation, not add it.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1dw:1440539392434:dwCareful though, you have to subtract everything.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1So what dare you left with? Try to deal with each column. 2x  2x?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would that make everything 0

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.12x  2x = 0 2y  2y = 0 The left side is clearly 0, good. 2  2 = ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so then the answer would be 0

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Noooo :O Check that last line again carefully!

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1\(\large\rm 22\ne0\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol im sorry im super confused

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1If you're at negative 2, and you take 2 away from that, you become even more negative.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Ok good! So we end up with this result: \(\large\rm 0=4\) Which is `false`. Therefore the system containing these two lines has NO solution. So again, this is not the one we're looking for. Your princess is in another castle :o

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok lol so now on to the other aswer right

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Let's check out the 3rd option: x + y = 1 2x + 2y = −2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0also im sorry math is the only thing i realy suck at

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so would we do the same thing we did last time

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Yah, that seems like a good idea.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Again, we multiply by 2 to match up the x's. 2(x + y = 1) 2x + 2y = −2 Giving us: 2x + 2y = 2 2x + 2y = −2

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1And then do some subtraction or addition to combine them. What are we gonna get this time? :o

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0umm the end parts on both sides are nagative so those be 0s

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Well notice that both equations are exactly the same now, ya? What happens when you subtract something from itself? You're gonna get 0. So good, in this case we end up with 0=0. So this system of two lines gives us infinitely many solutions!

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1yay team \c:/ we got it!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0also wich question was this

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1The only one that you asked :D lol I dunno, you didn't number it :d

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no i mean the question to the question we just worked on is it x + y = 1 2x + 2y = −2

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Line M was `given` to be x+y=1. And our `answer` that we obtained for line P is the third one, 2x+2y=2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok cool next question! :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Line Q is represented by the following equation: 2x + y = 11 Which equation completes the system that is satisfied by the solution (3, 5)? x + 2y = 15 x + y = 15 x + y = 8 x − y = 2

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1I gotta go make some foods. If you need further help, close this and open up another thread. This one is getting too long and messy. You can use the @ symbol to page someone for help. Example @zepdrix The people at the top of the lobby are usually a bunch of smarty pants. Include your question in title, it will help to get it answered faster. Don't just call it "need help with math". Just a little tip :) I'll try to come by and help when I can :) But the belly is rumblin at the moment!
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