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anonymous

  • one year ago

cos^2 - sin^2X ------over------ 1 - tan^2 X

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  1. Nnesha
    • one year ago
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    \[\huge\rm \frac{ \cos^2 x- \sin^2x }{ 1-\tan^2x}\]

  2. anonymous
    • one year ago
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    is cos^2X the answer

  3. Nnesha
    • one year ago
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    can you please tell me how u got cos^2x :=) thanks!

  4. anonymous
    • one year ago
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    do i have to

  5. Nnesha
    • one year ago
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    hmm just wanted some explanation you can explain in words like what ws ur first step

  6. anonymous
    • one year ago
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    cos^2 x - sin^2 x cos^2 x -sin^2 x cos^2 x - sin^2 x -------------------- = --------------------- = ---------------------- 1 - tan^2 cos^2 x sin^2 x cos^2 x - sin^2 x -------- - --------- ----------------------- cos^2 cos^2 cos^2 x cos^2 - x - sin^2 cos^2 x = ------------------------- x -------------- = cos^2 x 1 cos^2 -sin^2 x

  7. Nnesha
    • one year ago
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    PERFECT!

  8. anonymous
    • one year ago
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    thanks

  9. Nnesha
    • one year ago
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    thanks for showing ur work and you can use equation tool great job!

  10. anonymous
    • one year ago
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    yea i'm new so i don't really know how to use this yet

  11. Nnesha
    • one year ago
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    yeh i understand let me know if you have any question abt equation tool i can help :=)

  12. Nnesha
    • one year ago
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    or about latex

  13. anonymous
    • one year ago
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    ok thanks

  14. Nnesha
    • one year ago
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    np :=)

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