A particle is moving along the x-axis so that its position at t ≥ 0 is given by s(t) = (t)In(2t). Find the acceleration of the particle when the velocity is first zero.
None of these
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
well, we can find the derivative of position to get velocity, then we can take the derivative of velocity to get acceleration
do you know how to find the derivative of t*ln(2t)? we'll be using the product rule
Not the answer you are looking for? Search for more explanations.
oops i meant ln xD
no prob, now all we need to do is take the derivative of ln(2t). can you do that?
So the next derivative is 1/t
yup! our last step is to figure out what to plug in for t
the problem wants to find the acceleration when the velocity is 0, so we go back to our velocity equation and set it equal to 0, then solve for t
ln(2t) + 1 = 0
solve for t
i got 1/2e
right, t = 1/(2e), now we plug that back into our acceleration equation
1/t = 1/(1/(2e) = 1/(0.5e^-1) = 2e