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marigirl

  • one year ago

Integration question. The question is to find the integral of -cosec6xcis6x Plz help! I thought to first integrate -cosec6x Which is 1/sin (6x).....a little stuck

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  1. nincompoop
    • one year ago
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    can you rewrite that properly

  2. marigirl
    • one year ago
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    Integrate -cosec6xcot6x

  3. anonymous
    • one year ago
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    @nincompoop can you plz help me in a ques?

  4. nincompoop
    • one year ago
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    \(\huge \int -csc (6x) cot(6x) dx \) like this?

  5. marigirl
    • one year ago
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    Does cse mean cosec? If so then yes

  6. anonymous
    • one year ago
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    Ok so rewrite it as -1/sin(6x) * cos(6x)/sin(6x) then you get -cos(6x)/sin^2(6x) Then find the derivative of sin(6x) then your finished and use the formula integ of u^ndu=u^n+1/n+1 +c

  7. nincompoop
    • one year ago
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    \(\huge -\frac{1}{sin} = -csc \)

  8. nincompoop
    • one year ago
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    \(\huge \frac{1}{tan} = cot \)

  9. marigirl
    • one year ago
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    Does cse mean cosec? If so then yes

  10. nincompoop
    • one year ago
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    yes

  11. nincompoop
    • one year ago
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    u-sub

  12. anonymous
    • one year ago
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    Look thats it

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  13. nincompoop
    • one year ago
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    u = 6x du = 6 dx

  14. anonymous
    • one year ago
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    Did you understand it?

  15. nincompoop
    • one year ago
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    v = sin(u) dv = cos(u) du

  16. nincompoop
    • one year ago
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    those are you keys

  17. anonymous
    • one year ago
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    Your description and point is surely very feeble my friend so you're saying the Bible is demonic?

  18. anonymous
    • one year ago
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    In asking you a question that relates to what you've said hence fabricator

  19. nincompoop
    • one year ago
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    you really need to read the whole thing before you ruin your mind with fallacy

  20. anonymous
    • one year ago
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    No need since i spotted an error just from the very beginning which discourages me to continue this nonsense. Have a great day

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