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anonymous

  • one year ago

What is the missing value? https://static.k12.com/bank_packages/files/media/mathml_6a898366c833b4d7194aa8d29fc91e60db252b97_1.gif A. −10 B. −2 C. 2 D. 10

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  1. anonymous
    • one year ago
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    @jim_thompson5910

  2. jim_thompson5910
    • one year ago
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    hint: \[\LARGE \frac{x^a}{x^b} = x^{a-b}\]

  3. anonymous
    • one year ago
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    D 10?

  4. jim_thompson5910
    • one year ago
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    \[\LARGE \frac{x^a}{x^b} = x^{a-b}\] \[\LARGE \frac{3^{-6}}{3^{{}^\boxed{}}} = 3^{4}\] \[\LARGE \frac{3^{-6}}{3^{x}} = 3^{4}\] \[\LARGE 3^{-6-x} = 3^{4}\] set the exponents equal to one another and solve for x

  5. anonymous
    • one year ago
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    You lost me.

  6. jim_thompson5910
    • one year ago
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    where at?

  7. anonymous
    • one year ago
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    The last part

  8. jim_thompson5910
    • one year ago
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    when I went from \[\LARGE \frac{3^{-6}}{3^{x}} = 3^{4}\] to \[\LARGE 3^{-6-x} = 3^{4}\] ???

  9. anonymous
    • one year ago
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    Yes

  10. jim_thompson5910
    • one year ago
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    I used that rule I wrote in the hint. When you divide expressions like x^3 over x^2, you subtract the exponents

  11. anonymous
    • one year ago
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    Is it a? -10

  12. jim_thompson5910
    • one year ago
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    solve -6 - x = 10 for x

  13. jim_thompson5910
    • one year ago
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    sorry I meant -6 - x = 4

  14. anonymous
    • one year ago
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    negative - a negative = a positive = -6 - (-2) = 4 Right?

  15. jim_thompson5910
    • one year ago
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    -6 - (-2) = 4 is false

  16. jim_thompson5910
    • one year ago
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    -6 - (-2) = -4 is true so try again

  17. anonymous
    • one year ago
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    @jim_thompson5910

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  18. jim_thompson5910
    • one year ago
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    yes -6 - (-10) = -6 + 10 = 4

  19. anonymous
    • one year ago
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    OKAY THANKS

  20. jim_thompson5910
    • one year ago
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    no problem

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