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Theloshua
 one year ago
Find the domain of the following functions
Theloshua
 one year ago
Find the domain of the following functions

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Theloshua
 one year ago
Best ResponseYou've already chosen the best response.0\[f(x)=\frac{ \sqrt{x+2} }{ x5 }\]

Theloshua
 one year ago
Best ResponseYou've already chosen the best response.0\[g(x)=\frac{ x3 }{ \sqrt{x1}}\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1how far did you get with any of these?

Theloshua
 one year ago
Best ResponseYou've already chosen the best response.0like i need helpppp i haves so much work to do and so lil time, i dont wanna be up all nite...

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1well first off, hopefully you see that x5 in the denominator cannot be zero, so x5 = 0 leads to x = 5 if x = 5, then the denominator x5 is 0 that means x = 5 is NOT part of the domain

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1agreed so far?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1in the numerator of f(x), we have a radical you cannot take the square root of a negative number, so x+2 cannot be negative x+2 is either 0 or positive solve \[\Large x+2 \ge 0\] for x. Tell me what you get

Theloshua
 one year ago
Best ResponseYou've already chosen the best response.0x greater or equal to 2

Theloshua
 one year ago
Best ResponseYou've already chosen the best response.0oh wait, i already solved for this one. i need help with the second

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1so x cannot be 5 AND x has to be greater than or equal to 2

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1same idea with g(x) you cannot divide by 0 and you cannot take the square root of a negative number

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1what makes the denominator of g(x) equal to 0 ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1you can have 0 in the numerator though

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1what do you get when you solve sqrt(x1) = 0 for x?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1so if x = 1, then the whole denominator turns to 0 which is why x = 1 is NOT part of the domain

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1also, you need to ensure that x1 is never negative

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1solve x1 >= 0 for x to get what?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1x = 1 ? or x <= 1 ? or x >= 1 ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1greater than or equal to 1, yes

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1oh wait, nvm the "or equal to" part

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1x cannot equal 1 because it leads to a division by zero error

Theloshua
 one year ago
Best ResponseYou've already chosen the best response.0so? explaiiiin im confused tell me how to solve

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1you just said it: the domain is x > 1

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1any number larger than 1 will work as an input if x = 1 or smaller, then you run into problems

Theloshua
 one year ago
Best ResponseYou've already chosen the best response.0okay so the answer is x is not one and x is greater than 1?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1saying x > 1 implies that x is not equal to 1

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1you don't need to say them both if you just say x > 1

Theloshua
 one year ago
Best ResponseYou've already chosen the best response.0okay, so thats the answer tho
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