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anonymous

  • one year ago

I have homework that is due tomorrow and I need help with these two questions: 1. f(x) = -2(x - 1)^2 - 5 2. y = 1/2(x-3)^2 + 2

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  1. lfreeman1285
    • one year ago
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    Are you graphing them?

  2. anonymous
    • one year ago
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    yes and I have to find the axis of symmetry and the vertex.

  3. lfreeman1285
    • one year ago
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    This form gives you the vertex in it. y=a(x-h)^2 + k is the basic vertex form. And the vertex is (h, k). So in the first equation, the vertex would be (1, -5).

  4. anonymous
    • one year ago
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    Okay and to find the rest of the points you would just plug X into the original equation right? Or am I wrong?

  5. lfreeman1285
    • one year ago
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    Yup! It helps if you choose x values close to the vertex. The graph should form a u-shape (called a parabola) when you're done.

  6. anonymous
    • one year ago
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    Okay thanks. What about the AOS?

  7. lfreeman1285
    • one year ago
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    That's equal to the x value of the vertex. So for the first one it would be x=1.

  8. anonymous
    • one year ago
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    Oh. okay thanks!!!!!!!! :D

  9. lfreeman1285
    • one year ago
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    You're welcome! :)

  10. anonymous
    • one year ago
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    Is it the same thing for the other equation also?

  11. lfreeman1285
    • one year ago
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    Yes, not the same answers, but its in the same form, so you can solve it the same way.

  12. anonymous
    • one year ago
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    okay thanks you've been a real help! :D

  13. lfreeman1285
    • one year ago
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    You're welcome!

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