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anonymous
 one year ago
I have homework that is due tomorrow and I need help with these two questions:
1. f(x) = 2(x  1)^2  5
2. y = 1/2(x3)^2 + 2
anonymous
 one year ago
I have homework that is due tomorrow and I need help with these two questions: 1. f(x) = 2(x  1)^2  5 2. y = 1/2(x3)^2 + 2

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lfreeman1285
 one year ago
Best ResponseYou've already chosen the best response.2Are you graphing them?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes and I have to find the axis of symmetry and the vertex.

lfreeman1285
 one year ago
Best ResponseYou've already chosen the best response.2This form gives you the vertex in it. y=a(xh)^2 + k is the basic vertex form. And the vertex is (h, k). So in the first equation, the vertex would be (1, 5).

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay and to find the rest of the points you would just plug X into the original equation right? Or am I wrong?

lfreeman1285
 one year ago
Best ResponseYou've already chosen the best response.2Yup! It helps if you choose x values close to the vertex. The graph should form a ushape (called a parabola) when you're done.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay thanks. What about the AOS?

lfreeman1285
 one year ago
Best ResponseYou've already chosen the best response.2That's equal to the x value of the vertex. So for the first one it would be x=1.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh. okay thanks!!!!!!!! :D

lfreeman1285
 one year ago
Best ResponseYou've already chosen the best response.2You're welcome! :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is it the same thing for the other equation also?

lfreeman1285
 one year ago
Best ResponseYou've already chosen the best response.2Yes, not the same answers, but its in the same form, so you can solve it the same way.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay thanks you've been a real help! :D
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