I have homework that is due tomorrow and I need help with these two questions: 1. f(x) = -2(x - 1)^2 - 5 2. y = 1/2(x-3)^2 + 2

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I have homework that is due tomorrow and I need help with these two questions: 1. f(x) = -2(x - 1)^2 - 5 2. y = 1/2(x-3)^2 + 2

Algebra
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Are you graphing them?
yes and I have to find the axis of symmetry and the vertex.
This form gives you the vertex in it. y=a(x-h)^2 + k is the basic vertex form. And the vertex is (h, k). So in the first equation, the vertex would be (1, -5).

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Okay and to find the rest of the points you would just plug X into the original equation right? Or am I wrong?
Yup! It helps if you choose x values close to the vertex. The graph should form a u-shape (called a parabola) when you're done.
Okay thanks. What about the AOS?
That's equal to the x value of the vertex. So for the first one it would be x=1.
Oh. okay thanks!!!!!!!! :D
You're welcome! :)
Is it the same thing for the other equation also?
Yes, not the same answers, but its in the same form, so you can solve it the same way.
okay thanks you've been a real help! :D
You're welcome!

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