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anonymous

  • one year ago

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  1. anonymous
    • one year ago
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    Let: U={1,2,3,...,8} A={1,2,4,7} B={2,3,4} C={1,2,3,5,6} Find the following set: A' (upside down U) (B U C')

  2. jim_thompson5910
    • one year ago
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    first you'll need to find set C '

  3. jim_thompson5910
    • one year ago
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    C ' is the set of everything that is NOT in set C

  4. anonymous
    • one year ago
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    so {4,7,8}

  5. jim_thompson5910
    • one year ago
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    very good

  6. jim_thompson5910
    • one year ago
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    now union that set with set B

  7. misty1212
    • one year ago
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    \[\huge A'\cap \left(B\cup C'\right)\]

  8. jim_thompson5910
    • one year ago
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    to union two sets, you combine them to form one bigger set eg: A = {1,2,3} B = {2,7,9} A union B = {1,2,3,7,9} toss out any duplicates

  9. anonymous
    • one year ago
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    {2,3,4,7,8}

  10. jim_thompson5910
    • one year ago
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    correct

  11. jim_thompson5910
    • one year ago
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    now you'll need set A ' this is similar to set C '

  12. anonymous
    • one year ago
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    {3,5,6,8}

  13. jim_thompson5910
    • one year ago
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    finally intersect the set {3,5,6,8} with {2,3,4,7,8}

  14. jim_thompson5910
    • one year ago
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    ie list the numbers they have in common

  15. anonymous
    • one year ago
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    {3,8}

  16. jim_thompson5910
    • one year ago
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    and that's the final answer

  17. anonymous
    • one year ago
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    Awesome! thank you again, also I have two more questions if you could help? (Cross fingers)

  18. jim_thompson5910
    • one year ago
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    sure, go ahead

  19. anonymous
    • one year ago
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    ok hold on gotta type it lol

  20. anonymous
    • one year ago
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    Let: U={1,2,3,...,8} A={1,2,3,5} B={3,6,7} C={1,2,3,4,5} Find the following set: A' (upside down U) (B U C')

  21. anonymous
    • one year ago
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    Its similar, I know, but i gotta make sure :)

  22. jim_thompson5910
    • one year ago
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    did you get anywhere with this one?

  23. anonymous
    • one year ago
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    its pretty much the same isnt it, ok hold on ill work this out

  24. jim_thompson5910
    • one year ago
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    yeah it's the exact same expression to evaluate, just with different sets to work with

  25. anonymous
    • one year ago
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    A={4,6,7,8}

  26. jim_thompson5910
    • one year ago
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    A ' you mean?

  27. anonymous
    • one year ago
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    yes sorry

  28. anonymous
    • one year ago
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    ok then, C'= {6,7,8}

  29. jim_thompson5910
    • one year ago
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    both look good

  30. anonymous
    • one year ago
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    {4}

  31. anonymous
    • one year ago
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    wait nvm, both have {6,7,8} in common

  32. jim_thompson5910
    • one year ago
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    you mean you got {6,7,8} as your final answer?

  33. anonymous
    • one year ago
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    ah yes, ok now for the final question, thank you so much for hanging around by the way, your a life saver ;)

  34. jim_thompson5910
    • one year ago
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    no problem

  35. anonymous
    • one year ago
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