A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing


  • one year ago

I need help with this question, if an aluminum cube of mass 2.45 g and each side measuring 9.68 mm is dipped in the above cylinder containing 5.00 mL water, what will be the final water level in the cylinder? the above cylinder in the question above weighs 64.55 g

  • This Question is Open
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    You have to calculate the volume of the cube, LxLxL= L^3 = 9.68^3 convert the mm3 to mL and add this volume to the water volume (5.00mL) that is the final water level in the cylinder. The mass of the cylinder and the mass of the cube you dont need to solve this step of the problem

  2. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...


  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.