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marigirl

  • one year ago

Could you please explain mathematically what actually happens to the absolute value below

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  1. marigirl
    • one year ago
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    \[\ln \left| 2k^3-1 \right|=7.5\]

  2. marigirl
    • one year ago
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    Then I would go \[\left| 2k^3-1 \right|=e^(7.5)\]

  3. marigirl
    • one year ago
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    what will happen to the absolute function value now?

  4. IrishBoy123
    • one year ago
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    try\[2k^3−1=\pm e^{7.5}\]

  5. marigirl
    • one year ago
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    My question was to solve for k which the value is + or - 9.67 how do we 'get rid' of an absolute value function, or how do we balance an absolute value function in an equation Since absolute value function only look at positive values, I am a little confused with your response @IrishBoy123

  6. IrishBoy123
    • one year ago
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    let's say |x| = 3, then we can conclude that x = 3 OR x = -3 yes?

  7. IrishBoy123
    • one year ago
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    ie, in that example i give, we conclude \[x = \pm3\]

  8. IrishBoy123
    • one year ago
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    so if \(|x|=e^{7.5}\), you must consider \(x= \pm e^{7.5}\)

  9. IrishBoy123
    • one year ago
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    you should get two answers \[\sqrt[3]{\frac{1 \pm e^{7.5}}{2}}\]

  10. marigirl
    • one year ago
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    oh yea it makes sense now, I got k=9.67 and k=-9.66 Thanks heaps! I really appreciate it

  11. IrishBoy123
    • one year ago
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    \(\checkmark\)

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