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Hahawowoh
 one year ago
Cory has 15 diecast cars in his collection. Each year his collection increases by 20%. Roger has 40 cars in his collection. Each year he collects 1 additional car.
Part A: Write functions to represent Cory and Roger's collections throughout the years. (4 points)
Part B: How many cars does Cory have after 6 years? How many does Roger have after the same number of years? (2 points)
Part C: After approximately how many years is the number of cars that Cory and Roger have the same? Justify your answer mathematically. (4 points)
Hahawowoh
 one year ago
Cory has 15 diecast cars in his collection. Each year his collection increases by 20%. Roger has 40 cars in his collection. Each year he collects 1 additional car. Part A: Write functions to represent Cory and Roger's collections throughout the years. (4 points) Part B: How many cars does Cory have after 6 years? How many does Roger have after the same number of years? (2 points) Part C: After approximately how many years is the number of cars that Cory and Roger have the same? Justify your answer mathematically. (4 points)

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misty1212
 one year ago
Best ResponseYou've already chosen the best response.0you are not getting an answer because there is no information with which to answer it

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0to increase a number by \(20\%\) multiply it by \(100\%+20\%=120\%=1.2\) so a good function for cory is \[15\times 1.2^t\]

Hahawowoh
 one year ago
Best ResponseYou've already chosen the best response.0I have everything just part c

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0i guess you are supposed to solve \[t+40=15\times (1.2)^t\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0it says "approximately" so i would use this http://www.wolframalpha.com/input/?i=t%2B40%3D15%281.2%29%5Et

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0or since you were already asked how many each had in six years, and since those numbers are almost equal, say "six"
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