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anonymous

  • one year ago

Use the distributive property to simplify the expression. -6(1^2+3)-2(1^2-2)

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  1. misty1212
    • one year ago
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    HI!!

  2. misty1212
    • one year ago
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    i am going to guess that there is a typo there very rarely do you see \(1^2\)

  3. misty1212
    • one year ago
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    \[-6(1^2+3)-2(1^2-2)\]is a number no need for the distributive law could it be \[-6(x^2+3)-2(x^2-2)\]or something like that?

  4. anonymous
    • one year ago
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    yeah it was like that but it wouldn't let me put it like that

  5. misty1212
    • one year ago
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    with the \(x\)?

  6. anonymous
    • one year ago
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    it doesn't say

  7. anonymous
    • one year ago
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    it just say t^2

  8. misty1212
    • one year ago
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    can you post a screen shot or an attachment?

  9. misty1212
    • one year ago
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    ooh it is a \(t\) ok

  10. misty1212
    • one year ago
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    \[-6(t^2+3)-2(t^2-2)\] right?

  11. anonymous
    • one year ago
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    -6(t^2+3)-2(t^2-2)

  12. misty1212
    • one year ago
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    ok multiply each term in the first parentheses by \(-6\) what do you get?

  13. anonymous
    • one year ago
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    idk

  14. anonymous
    • one year ago
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    I think I calculated it wrong

  15. misty1212
    • one year ago
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    \[-6(t^2+3)=-6\times t^2+-6\times 3\] is a start

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