anonymous
  • anonymous
Use the distributive property to simplify the expression. -6(1^2+3)-2(1^2-2)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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misty1212
  • misty1212
HI!!
misty1212
  • misty1212
i am going to guess that there is a typo there very rarely do you see \(1^2\)
misty1212
  • misty1212
\[-6(1^2+3)-2(1^2-2)\]is a number no need for the distributive law could it be \[-6(x^2+3)-2(x^2-2)\]or something like that?

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anonymous
  • anonymous
yeah it was like that but it wouldn't let me put it like that
misty1212
  • misty1212
with the \(x\)?
anonymous
  • anonymous
it doesn't say
anonymous
  • anonymous
it just say t^2
misty1212
  • misty1212
can you post a screen shot or an attachment?
misty1212
  • misty1212
ooh it is a \(t\) ok
misty1212
  • misty1212
\[-6(t^2+3)-2(t^2-2)\] right?
anonymous
  • anonymous
-6(t^2+3)-2(t^2-2)
misty1212
  • misty1212
ok multiply each term in the first parentheses by \(-6\) what do you get?
anonymous
  • anonymous
idk
anonymous
  • anonymous
I think I calculated it wrong
misty1212
  • misty1212
\[-6(t^2+3)=-6\times t^2+-6\times 3\] is a start

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