## anonymous one year ago Use the distributive property to simplify the expression. -6(1^2+3)-2(1^2-2)

1. misty1212

HI!!

2. misty1212

i am going to guess that there is a typo there very rarely do you see $$1^2$$

3. misty1212

$-6(1^2+3)-2(1^2-2)$is a number no need for the distributive law could it be $-6(x^2+3)-2(x^2-2)$or something like that?

4. anonymous

yeah it was like that but it wouldn't let me put it like that

5. misty1212

with the $$x$$?

6. anonymous

it doesn't say

7. anonymous

it just say t^2

8. misty1212

can you post a screen shot or an attachment?

9. misty1212

ooh it is a $$t$$ ok

10. misty1212

$-6(t^2+3)-2(t^2-2)$ right?

11. anonymous

-6(t^2+3)-2(t^2-2)

12. misty1212

ok multiply each term in the first parentheses by $$-6$$ what do you get?

13. anonymous

idk

14. anonymous

I think I calculated it wrong

15. misty1212

$-6(t^2+3)=-6\times t^2+-6\times 3$ is a start