anonymous
  • anonymous
Find −3a2 − b3 + 3c2 − 2b3 if a = 2, b = −1, and c = 3.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
-3(2)^2 +1^3 + 3(3)^2 – 2(-1)^3
Vocaloid
  • Vocaloid
^ ok, you've plugged in the numbers correctly, all you have to do is calculate what that expression is equal to...
anonymous
  • anonymous
I got 14 but I dont know if its correct

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Vocaloid
  • Vocaloid
well, let's take it step by step: -3(2)^2 = ?
anonymous
  • anonymous
-6^2 or -3(4)?
Vocaloid
  • Vocaloid
it's -3(4) remember, the exponent only applies to the number next to it
anonymous
  • anonymous
Okay -3(4)
Vocaloid
  • Vocaloid
1^3 = ?
anonymous
  • anonymous
1
Vocaloid
  • Vocaloid
good. 3(3)^2 = ? (again, remember that the exponent only applies to the number next to it)
anonymous
  • anonymous
3(9)
Vocaloid
  • Vocaloid
good, – 2(-1)^3 = ?
anonymous
  • anonymous
Above, why would the 1 be positive if it was negative in the equation?
anonymous
  • anonymous
-2(-1)
Vocaloid
  • Vocaloid
if b = -1 then -b^3 = -(-1)(-1)(-1) = 1
anonymous
  • anonymous
Ohhhhhh. Okay I get it. Gotcha. Okay continue (:
Vocaloid
  • Vocaloid
and yes, – 2(-1)^3 = -1 so we put everything together: -3(2)^2 +1^3 + 3(3)^2 – 2(-1)^3 = -3(4) + 1 + 3(9) -2(-1) can you take over from here?
Vocaloid
  • Vocaloid
g2g but the final answer should be 18
anonymous
  • anonymous
Got it. Thank you so much

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