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anonymous

  • one year ago

What is the value of x if e^3x+6=8?

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  1. Nnesha
    • one year ago
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    \[\huge\rm e^{3x+6}=8\] how would you cancel out the `e` ? do you know ?

  2. anonymous
    • one year ago
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    subtract it on both sides?

  3. anonymous
    • one year ago
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    no nvm

  4. Nnesha
    • one year ago
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    no you should take `ln` both sides to cancel out the `e` here is an example \[\huge\rm \cancel{ln e}^x = x\]

  5. Nnesha
    • one year ago
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    if hte question is \[\huge\rm e^9\] i would take ln \[\huge\rm ln e^9\] which cancel out the e answer would by 9

  6. anonymous
    • one year ago
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    mc020-2.jpg mc020-3.jpg mc020-4.jpg mc020-5.jpg

  7. Nnesha
    • one year ago
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    ???

  8. Nnesha
    • one year ago
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    take ln both sides just like u take square or square root both sides

  9. anonymous
    • one year ago
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    i think x= ln6-8/3 ?

  10. Nnesha
    • one year ago
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    ln = natural log

  11. Nnesha
    • one year ago
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    no

  12. anonymous
    • one year ago
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    oh x= ln8+6/3

  13. Nnesha
    • one year ago
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    don't post answer choices one by one...

  14. Nnesha
    • one year ago
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    \[\huge\rm lne^{3x+6}=ln8\] noow go from here!

  15. Nnesha
    • one year ago
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    ln and e cancel each other out!

  16. anonymous
    • one year ago
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    so 3x+6=ln8 is whats left?

  17. Nnesha
    • one year ago
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    yes right now solve for x!!

  18. Nnesha
    • one year ago
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    how would you cancel out the 6 from the left side ?

  19. anonymous
    • one year ago
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    subtract 6

  20. Nnesha
    • one year ago
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    good right so x= ??

  21. anonymous
    • one year ago
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    8-6/3

  22. Nnesha
    • one year ago
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    it's not just 8

  23. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @Nnesha \[\huge\rm lne^{3x+6}=ln8\] noow go from here! \(\color{blue}{\text{End of Quote}}\) ln8 not just 8

  24. anonymous
    • one year ago
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    ln8-6/3 srry

  25. Nnesha
    • one year ago
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    looks good!

  26. anonymous
    • one year ago
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    thank you

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