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  • one year ago

Genetics: Sex-linked inheritance calculation help

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  1. Calculator
    • one year ago
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    Brown-eyed girl with normal sight get married to the brown-eyed man with normal sight. The father of the girl was blue-eyed and colour-blind. What is F1? It is known that brown eyes are inherited as autosome dominant character and the gene of colour blindness - as recessive and X-linked.

  2. Calculator
    • one year ago
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    This is my work, I can't get the answer

  3. Calculator
    • one year ago
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    Answers are: ¼ - daughters with brown eyes and normal vision; ¼ - daughters with blue eyes and normal vision; 1/8 – sons with brown eyes and normal vision; 1/8 - sons with brown eyes and daltonism; 1/8 - sons with blue eyes and normal vision; 1/8 - sons with blue eyes and daltonism;

  4. Calculator
    • one year ago
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    I've gotten the 1/4 daughters with blue eyes + normal vision, but can't seem to get 1/4 daughter with brown + normal vision

  5. Abhisar
    • one year ago
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    3/8 girls will be brown+normal

  6. Abhisar
    • one year ago
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    You can find this without drawing the punnet square too. For the cross \(\sf BbX^AX\) (female) \(\times \sf BbXY\) (male) Probability of brown = 3/4 Probability of female = 1/2 Probability of Normal vision= 1 (color blindness is recessive x-linked, and father has no \(\sf X^A\) allele) Probability of brown + female + normal vision = \(\sf Large \frac{3}{4} \times \frac{1}{2} \times \frac{1}{1}=\frac{6}{16}\) So, 6 among 16 offsprings will be girl+Normal vision+Brown color

  7. Calculator
    • one year ago
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    But the answers are 1/4 for daughters with brown eyes and normal vision? Are the answers incorrect?

  8. anonymous
    • one year ago
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    its quite complicated but ain't impossible.. the answer is 1/4 for daughters with brown eyes and normal vision...

  9. Abhisar
    • one year ago
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    @harishk , don't just post your answer. It will be better if you back your statement with some valid reason or work out.

  10. Abhisar
    • one year ago
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    There was another possibility, if we take male as \(\sf BBXY\) and cross it with female \(\sf BbX^AX\) then probability of females with brown eyes and normal sight comes 1/2

  11. Abhisar
    • one year ago
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    |dw:1440674332059:dw|

  12. Abhisar
    • one year ago
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    |dw:1440674566586:dw|

  13. Abhisar
    • one year ago
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    @shreehari499

  14. Abhisar
    • one year ago
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    @Calculator , are you able to find out any error in the above cross?

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