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anonymous

  • one year ago

graph -2x+4y=4 for the domain D:{-8,-4,0,4,8}

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  1. anonymous
    • one year ago
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    @pooja195

  2. anonymous
    • one year ago
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    are you asking if it is righ or what

  3. anonymous
    • one year ago
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    no thats the question

  4. anonymous
    • one year ago
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    okay hold on

  5. anonymous
    • one year ago
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    do you have to type in the anwser or is there muliple anwsers

  6. anonymous
    • one year ago
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    u have to type

  7. anonymous
    • one year ago
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    okay i thing that this is it y = 3x -13

  8. anonymous
    • one year ago
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    how did u figure that out

  9. anonymous
    • one year ago
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    @texaschic101

  10. anonymous
    • one year ago
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    @mathmath333

  11. anonymous
    • one year ago
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    1. (a) Is the graph of a circle a graph of a function? Yes or no (b) Find the center and the radius of the circle represented by the equation x^2 + y^2 + 10x – 4y – 7 = 0 x^2+10x+25 + y^2 -4y + 4 = 7+25+4 (x+5)^2 + (y-2)^2 = 36 ----- Center: (-5,2) ; radius = 6 ----------- ----------- -------- 2. Let g(x)= 9-x/6+x (a) Find g(–1) g(-1) = (9 + 1)/(6-1) = 2 ----------- ----------- -------- (b) Find g(t + 1) and simplify. g(t+1) = (9-(t+1))/(6+(t+1)) g(t+1) = (8-t)/(7+t) ----------- ----------- ------- (c) Find the domain of the function Let g(x)= 9-x/6+x Domain: All Real Numbers except x=-6

  12. anonymous
    • one year ago
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    3.Consider the points (4, –1) and (7, 8). (a) Find the midpoint of the line segment with the given endpoints. x = (4+7)/2 = 11/2 y = (-1+8)/2 = 7/2 ----------- ----------- - (b) Find the distance between the points. Give an exact answer (simplified as much as possible), and also an approximation to three decimal places. d = sqrt[(8--1)^2+(7-4)^2] = sqrt(117) ----------- ----------- ----------- ------ (c) Find the slope of the line passing through the two given points slope = (8--1)/(7-4) = 9/3 = 3 ----------- --------- (d) Find the equation of the line passing through the two given points. 8 = 3*7 + b b = -13 Anwser is y = 3x -13

  13. anonymous
    • one year ago
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    thank you

  14. anonymous
    • one year ago
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    ur welcome

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spraguer (Moderator)
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