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anonymous

  • one year ago

Find the midpoint between two points on a coordinate plane whose coordinates are (5, 7) and (-3, 1). (2, 8) (1, 4) (8, 8) (4, 4)

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  1. calculusxy
    • one year ago
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    For this problem, just find the average of the x-values and the y-values. For your answer, to find the x-coordinate: \[x-value = \frac{ 5+ (-3) }{ 2 }\] y-value: \[y - value = \frac{ 7 + 1 }{ 2 }\]

  2. triciaal
    • one year ago
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    |dw:1440610001038:dw|

  3. calculusxy
    • one year ago
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    @ltj12345. Did you get your answer?

  4. anonymous
    • one year ago
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    a

  5. triciaal
    • one year ago
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    the midpoint is have the distance between the 2 points separate the x and the y

  6. calculusxy
    • one year ago
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    Remember that you need to find the averages. Choice A is halfway there, but just divide the x- and y-coordinates by two to get the final answer.

  7. anonymous
    • one year ago
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    c

  8. calculusxy
    • one year ago
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    \[\frac{ 2 }{ 2 } = x-coordinate\] \[\frac{ 8 }{ 2 } = y- coordinate\]

  9. calculusxy
    • one year ago
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    @ltj12345. Find the answers to the expressions that I gave you.

  10. triciaal
    • one year ago
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    |dw:1440610300725:dw|

  11. anonymous
    • one year ago
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    (8,8)

  12. calculusxy
    • one year ago
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    \[\frac{ 2 }{ 2 } = 1\] \[\frac{ 8 }{ 2 } = 4\] Answer: \[(1,4)\]

  13. anonymous
    • one year ago
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    thanks

  14. calculusxy
    • one year ago
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    You're welcome :) I hope you understood the concept.

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