help me

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What do you think it is?
c

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Other answers:

am i right
i am pretty sure c is correct but let me check 1 last time
what is the x at the bottom of the problem
idk lol
Note: as x approaches 1 the denominator approaches zero
you can use l'hopitals theorem to do this find the derivative of the numerator and the denominator and plug in x = 1
are you familiar with this?
\[\frac{x^3+5 x^2+3 x-9}{x-1}=x^2+6 x+9 \]When x = 0, x^2+6 x+9=9
omg to many people helping lol this is consufing
c is not right
ok then what is
have you done l'hopitals rule in calculus?
i have not
oh well i can't think of any other way to do this. There probably is though...
man i just need to answer this question is there aother way to help with this
oh ok if we factor the numerators we get (x - 1)(x^2 + 6x + 9) ------------------ (x - 1) so the x-1 cancels out to give x^2 + 6x + 9
now plug in x = 1 into x^2 + 6x + 9 and see what you get
i got 16
thats the answer
ok?

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