## anonymous one year ago help me

1. anonymous

2. anonymous

What do you think it is?

3. anonymous

c

4. anonymous

am i right

5. anonymous

i am pretty sure c is correct but let me check 1 last time

6. anonymous

what is the x at the bottom of the problem

7. anonymous

idk lol

8. welshfella

Note: as x approaches 1 the denominator approaches zero

9. welshfella

you can use l'hopitals theorem to do this find the derivative of the numerator and the denominator and plug in x = 1

10. welshfella

are you familiar with this?

11. anonymous

$\frac{x^3+5 x^2+3 x-9}{x-1}=x^2+6 x+9$When x = 0, x^2+6 x+9=9

12. anonymous

omg to many people helping lol this is consufing

13. welshfella

c is not right

14. anonymous

ok then what is

15. welshfella

have you done l'hopitals rule in calculus?

16. anonymous

i have not

17. welshfella

oh well i can't think of any other way to do this. There probably is though...

18. anonymous

man i just need to answer this question is there aother way to help with this

19. welshfella

oh ok if we factor the numerators we get (x - 1)(x^2 + 6x + 9) ------------------ (x - 1) so the x-1 cancels out to give x^2 + 6x + 9

20. welshfella

now plug in x = 1 into x^2 + 6x + 9 and see what you get

21. anonymous

i got 16

22. welshfella