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  • one year ago

Find period, domain, and range of y= 3 csc (3x + pi) -2 y=3 csc 3 (x+ pi/3) -2 but I'm stuck from here. This is review from last year, but I've totally forgotten everything about trig functions. Not looking for just answers but also explanations!

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  1. freckles
    • one year ago
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    The period of y=csc(x) is 2pi. So the period of y=csc(bx) is 2pi/|b|. --- y=sin(x) on [-2pi,2pi] looks like: |dw:1440611891389:dw| We can see the period is 2pi. The reciprocal function of y=sin(x) is y=csc(x). So noticed the zeros of y=sin(x) on [-2pi,2pi], they were at x=-2pi,-pi,0,pi,2pi y=csc(x) will be undefined there. Notice where sin(x)=1 on [-2pi,2pi], they were at x=-3pi/2,x=pi/2 well this is where csc(x)=1 also since the reciprocal of 1 is still 1. Notice where sin(x)=-1 on [-2pi,2pi], they were at x=-pi/2,3pi/2 well this where csc(x)=-1 since the reciprocal of -1 is still -1. The graph of y=csc(x) looks like: |dw:1440612297776:dw| you can also from this graph that the range is (-inf,-1] union [1,inf) and the domain is everything but where we had the zeros fro sin(x) which was npi where n is integer -- Anyways...we have \[\csc(x) \le -1 \text{ or } \csc(x) \ge 1 \text{ from the range } \\ \text{ this holds for any input } \\ \csc(3x+\pi) \le -1 \text{ or } \csc(3x+\pi) \ge 1 \\ \text{ multiply both sides by 3 and then subtract both sides by 2 } \\ \text{ \to find range of } y=3\csc(3x+\pi)-2\] -- Now for the domain part... You could solve the following equation to find out what numbers to exclude: \[\sin(3x+\pi)=0\]

  2. cassieforlife5
    • one year ago
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    Thank you for the awesome details! I'm still a bit confused but I'll try and go over it a few times. Could you help with the equation for finding the domain as well?

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