How do I find the most basic atom (most likely to accept H+) in a molecule?

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How do I find the most basic atom (most likely to accept H+) in a molecule?

Organic
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There are two OH groups and a NH2 group...
To accept H+ (protons) The basic atom should have lone pairs :)
Thanks! All three possibilities have lone pairs. One lone pair on the N and 2 lone pairs on the O

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It depends on the acidity and basicity of the lone pairs
that's how I thought too !
The one that is more basic is the one that H+ will attach to
This is a question of Basicity; which one is most likely to accept an H+ means the element that is more likely to donate it's a pair of electrons. for this I relate this concept to how nucleophilic the element is, meaning it's tendency to donate a pair of electrons. Oxygen and Nitrogen; oxygen is more electronegative that nitrogen, meaning that it's less likely to donate electrons. Nitrogen; is less electronegative more likely to give up a pair of electrons and accept an H+ I would say it's the nitrogen
@taramgrant0543664 But I thought in the way orgoldfish thought. Cuz when u have more lone pairs the ability to attract protons is high. Thus the basicity increases due to the attraction of higher number of H+
I feel that the molecule needs to be more likely to give up it's electrons and take on a proton. if something is acidic then it's more likely that it's going to give up a proton, and it's conjugate base is going to be stable, that atom must be able to stabilize the negative charge well other wise it wouldn't want to lose the proton.
The lone pair on the neutral N in the NH3 is more stable than the anionic lone pair on O in OH. Therefore, the lone pair on NH3 is less basic. The conjugate acid of OH is water which has a pKa = 15.7. The conjugate acid of NH3 is NH4+ which has a pKa = 9. Therefore, NH3 has the more acidic conjugate acid and is the weaker base. Basic atoms in a molecule will have lone pairs, to accept the proton(s). So I'm thinking oxygen
I agree with taramgrant
@abb0t thoughts?
Perhaps an example might help?

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