please help.... i will attach question

- anonymous

please help.... i will attach question

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- anonymous

\[x ^{2}+y ^{2} = 5\]
graph the circle or ellipses....

- anonymous

would the radius be sqrt of 5

- anonymous

@freckles Can you help

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## More answers

- amilapsn

@sarahg7 yep

- anonymous

but how exactly do i graph that?

- anonymous

my center would be at the origin.. i think

- anonymous

Okay so because there isn't any numbers next to the exponents, the center of the circle would start at the point (0,0).
The radius would be 5...

- anonymous

i thought it would be sqrt of 5

- anonymous

bc 5= r^2

- amilapsn

|dw:1440612710148:dw|

- anonymous

dont get how you gor rhat^

- freckles

@amilapsn was just graphing a random circle with center (h,k) and radius r.

- freckles

your (h,k) is (0,0) and your radius is sqrt(5) has someone suggested earlier.
So your radius is approximately 2.2 units in length.

- freckles

so you would go to your center...And go up from 2.2 units put a dot
Go back to the center go down 2.2 units put a dot
Go back to the center count left 2.2 units put a dot
Go back to the center count right 2.2 units put a dot

- freckles

connect the dots forming a circle

- anonymous

oh gotchaaa!!! the other person was confusing me when they said the radius is 5

- freckles

missed that
it should be sqrt(5)
it was probably a mistype on his part

- anonymous

too make sure i understnad
\[x ^{a}+y ^{2} = 16\]

- freckles

a is 2 right?

- anonymous

origin is (0,0). and i just go 4 units up, right, left, and down. (radius =4)
yess sorry, mistype..

- freckles

yep connect all those dots you found making it as circley looking as possible

- anonymous

lol connecting it to look circley is the hardest part... but what about a problem like..
\[\frac{ x ^{2} }{ 1} + \frac{ y ^{2} }{ 9 } = 1\]

- freckles

that one is not a circle

- freckles

this one is ellipse

- freckles

\[\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1 \text{ has center } (h,k) \]
ok... now I don't know if these are the technical terms for it...
the thing under the x part tells us the "horizontal radius" from the center
the thing under the y part tells us the "vertical radius" from the center

- freckles

\[\frac{x^2}{4}+\frac{y^2}{25}=1 \\ \text{ has center } (0,0) \\ \text{ and horizontal radius } \sqrt{4}=2 \\ \text{ and vertical radius } \sqrt{25}=5\]

- freckles

this would look like:
|dw:1440614566689:dw|
now this was horribly drawn

- freckles

but I just counted up 5 from the center and down 5 from the center
and I counted right and left from the center 2 units

- anonymous

so for my equation itd have a horizontal radius of 1 and a vertical radius of 3

- freckles

yes

- anonymous

whic means 3 units up an down and one unit left and right

- freckles

and like I said before those are probably not the technical terms but it is how I remember how to draw the things

- freckles

yep

- anonymous

Thank youuu!

- freckles

np

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