1. anonymous

$x ^{2}+y ^{2} = 5$ graph the circle or ellipses....

2. anonymous

would the radius be sqrt of 5

3. anonymous

@freckles Can you help

4. amilapsn

@sarahg7 yep

5. anonymous

but how exactly do i graph that?

6. anonymous

my center would be at the origin.. i think

7. anonymous

Okay so because there isn't any numbers next to the exponents, the center of the circle would start at the point (0,0). The radius would be 5...

8. anonymous

i thought it would be sqrt of 5

9. anonymous

bc 5= r^2

10. amilapsn

|dw:1440612710148:dw|

11. anonymous

dont get how you gor rhat^

12. freckles

@amilapsn was just graphing a random circle with center (h,k) and radius r.

13. freckles

14. freckles

so you would go to your center...And go up from 2.2 units put a dot Go back to the center go down 2.2 units put a dot Go back to the center count left 2.2 units put a dot Go back to the center count right 2.2 units put a dot

15. freckles

connect the dots forming a circle

16. anonymous

oh gotchaaa!!! the other person was confusing me when they said the radius is 5

17. freckles

missed that it should be sqrt(5) it was probably a mistype on his part

18. anonymous

too make sure i understnad $x ^{a}+y ^{2} = 16$

19. freckles

a is 2 right?

20. anonymous

origin is (0,0). and i just go 4 units up, right, left, and down. (radius =4) yess sorry, mistype..

21. freckles

yep connect all those dots you found making it as circley looking as possible

22. anonymous

lol connecting it to look circley is the hardest part... but what about a problem like.. $\frac{ x ^{2} }{ 1} + \frac{ y ^{2} }{ 9 } = 1$

23. freckles

that one is not a circle

24. freckles

this one is ellipse

25. freckles

$\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1 \text{ has center } (h,k)$ ok... now I don't know if these are the technical terms for it... the thing under the x part tells us the "horizontal radius" from the center the thing under the y part tells us the "vertical radius" from the center

26. freckles

$\frac{x^2}{4}+\frac{y^2}{25}=1 \\ \text{ has center } (0,0) \\ \text{ and horizontal radius } \sqrt{4}=2 \\ \text{ and vertical radius } \sqrt{25}=5$

27. freckles

this would look like: |dw:1440614566689:dw| now this was horribly drawn

28. freckles

but I just counted up 5 from the center and down 5 from the center and I counted right and left from the center 2 units

29. anonymous

so for my equation itd have a horizontal radius of 1 and a vertical radius of 3

30. freckles

yes

31. anonymous

whic means 3 units up an down and one unit left and right

32. freckles

and like I said before those are probably not the technical terms but it is how I remember how to draw the things

33. freckles

yep

34. anonymous

Thank youuu!

35. freckles

np