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please help.... i will attach question

Mathematics
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\[x ^{2}+y ^{2} = 5\] graph the circle or ellipses....
would the radius be sqrt of 5
@freckles Can you help

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but how exactly do i graph that?
my center would be at the origin.. i think
Okay so because there isn't any numbers next to the exponents, the center of the circle would start at the point (0,0). The radius would be 5...
i thought it would be sqrt of 5
bc 5= r^2
|dw:1440612710148:dw|
dont get how you gor rhat^
@amilapsn was just graphing a random circle with center (h,k) and radius r.
your (h,k) is (0,0) and your radius is sqrt(5) has someone suggested earlier. So your radius is approximately 2.2 units in length.
so you would go to your center...And go up from 2.2 units put a dot Go back to the center go down 2.2 units put a dot Go back to the center count left 2.2 units put a dot Go back to the center count right 2.2 units put a dot
connect the dots forming a circle
oh gotchaaa!!! the other person was confusing me when they said the radius is 5
missed that it should be sqrt(5) it was probably a mistype on his part
too make sure i understnad \[x ^{a}+y ^{2} = 16\]
a is 2 right?
origin is (0,0). and i just go 4 units up, right, left, and down. (radius =4) yess sorry, mistype..
yep connect all those dots you found making it as circley looking as possible
lol connecting it to look circley is the hardest part... but what about a problem like.. \[\frac{ x ^{2} }{ 1} + \frac{ y ^{2} }{ 9 } = 1\]
that one is not a circle
this one is ellipse
\[\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1 \text{ has center } (h,k) \] ok... now I don't know if these are the technical terms for it... the thing under the x part tells us the "horizontal radius" from the center the thing under the y part tells us the "vertical radius" from the center
\[\frac{x^2}{4}+\frac{y^2}{25}=1 \\ \text{ has center } (0,0) \\ \text{ and horizontal radius } \sqrt{4}=2 \\ \text{ and vertical radius } \sqrt{25}=5\]
this would look like: |dw:1440614566689:dw| now this was horribly drawn
but I just counted up 5 from the center and down 5 from the center and I counted right and left from the center 2 units
so for my equation itd have a horizontal radius of 1 and a vertical radius of 3
yes
whic means 3 units up an down and one unit left and right
and like I said before those are probably not the technical terms but it is how I remember how to draw the things
yep
Thank youuu!
np

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