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anonymous

  • one year ago

please help.... i will attach question

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  1. anonymous
    • one year ago
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    \[x ^{2}+y ^{2} = 5\] graph the circle or ellipses....

  2. anonymous
    • one year ago
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    would the radius be sqrt of 5

  3. anonymous
    • one year ago
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    @freckles Can you help

  4. amilapsn
    • one year ago
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    @sarahg7 yep

  5. anonymous
    • one year ago
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    but how exactly do i graph that?

  6. anonymous
    • one year ago
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    my center would be at the origin.. i think

  7. anonymous
    • one year ago
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    Okay so because there isn't any numbers next to the exponents, the center of the circle would start at the point (0,0). The radius would be 5...

  8. anonymous
    • one year ago
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    i thought it would be sqrt of 5

  9. anonymous
    • one year ago
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    bc 5= r^2

  10. amilapsn
    • one year ago
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    |dw:1440612710148:dw|

  11. anonymous
    • one year ago
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    dont get how you gor rhat^

  12. freckles
    • one year ago
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    @amilapsn was just graphing a random circle with center (h,k) and radius r.

  13. freckles
    • one year ago
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    your (h,k) is (0,0) and your radius is sqrt(5) has someone suggested earlier. So your radius is approximately 2.2 units in length.

  14. freckles
    • one year ago
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    so you would go to your center...And go up from 2.2 units put a dot Go back to the center go down 2.2 units put a dot Go back to the center count left 2.2 units put a dot Go back to the center count right 2.2 units put a dot

  15. freckles
    • one year ago
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    connect the dots forming a circle

  16. anonymous
    • one year ago
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    oh gotchaaa!!! the other person was confusing me when they said the radius is 5

  17. freckles
    • one year ago
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    missed that it should be sqrt(5) it was probably a mistype on his part

  18. anonymous
    • one year ago
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    too make sure i understnad \[x ^{a}+y ^{2} = 16\]

  19. freckles
    • one year ago
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    a is 2 right?

  20. anonymous
    • one year ago
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    origin is (0,0). and i just go 4 units up, right, left, and down. (radius =4) yess sorry, mistype..

  21. freckles
    • one year ago
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    yep connect all those dots you found making it as circley looking as possible

  22. anonymous
    • one year ago
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    lol connecting it to look circley is the hardest part... but what about a problem like.. \[\frac{ x ^{2} }{ 1} + \frac{ y ^{2} }{ 9 } = 1\]

  23. freckles
    • one year ago
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    that one is not a circle

  24. freckles
    • one year ago
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    this one is ellipse

  25. freckles
    • one year ago
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    \[\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1 \text{ has center } (h,k) \] ok... now I don't know if these are the technical terms for it... the thing under the x part tells us the "horizontal radius" from the center the thing under the y part tells us the "vertical radius" from the center

  26. freckles
    • one year ago
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    \[\frac{x^2}{4}+\frac{y^2}{25}=1 \\ \text{ has center } (0,0) \\ \text{ and horizontal radius } \sqrt{4}=2 \\ \text{ and vertical radius } \sqrt{25}=5\]

  27. freckles
    • one year ago
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    this would look like: |dw:1440614566689:dw| now this was horribly drawn

  28. freckles
    • one year ago
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    but I just counted up 5 from the center and down 5 from the center and I counted right and left from the center 2 units

  29. anonymous
    • one year ago
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    so for my equation itd have a horizontal radius of 1 and a vertical radius of 3

  30. freckles
    • one year ago
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    yes

  31. anonymous
    • one year ago
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    whic means 3 units up an down and one unit left and right

  32. freckles
    • one year ago
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    and like I said before those are probably not the technical terms but it is how I remember how to draw the things

  33. freckles
    • one year ago
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    yep

  34. anonymous
    • one year ago
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    Thank youuu!

  35. freckles
    • one year ago
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    np

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