## YumYum247 one year ago Guelp please!!!

1. YumYum247

Can someone please check my work???

2. YumYum247

hint: I suppose that the motion of your flowerpot is a vertical motion. Time needed to flowerpot to reach the earth surface is: $\Large \frac{{{v_0}}}{g}\left\{ {1 + \sqrt {\frac{1}{2} + \frac{{2g{h_0}}}{{v_0^2}}} } \right\}$ where v0= 1m/sec and h0 is the maximum height reached by our flowerpot the final speed of our flowerpot, is: $\Large \sqrt {2g{h_0} + v_0^2}$ Please use those information, and you will get your answers