mathmath333
  • mathmath333
Probability question
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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mathmath333
  • mathmath333
\(\large \color{black}{\begin{align} & \normalsize \text{A man and woman appear in an interview for 2 vacancies}\hspace{.33em}\\~\\ & \normalsize \text{of same post.The probablity of man's selection is }\ \dfrac{1}{4} \text{and that of } \hspace{.33em}\\~\\ & \normalsize \text{woman's selection is }\ \dfrac{1}{3}\ \text{What is the probablity that both } \hspace{.33em}\\~\\ & \normalsize \text{will be selected} \hspace{.33em}\\~\\ & a.)\ \dfrac{1}{12} \hspace{.33em}\\~\\ & b.)\ \dfrac{1}{3} \hspace{.33em}\\~\\ & c.)\ \dfrac{2}{5} \hspace{.33em}\\~\\ & d.)\ \dfrac{3}{7} \hspace{.33em}\\~\\ \end{align}}\)
ganeshie8
  • ganeshie8
Hint: they are independent events
ganeshie8
  • ganeshie8
man's selection doesn't depend on women's and vice versa

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mathmath333
  • mathmath333
\(\large \color{black}{\begin{align} & P(A\cap B)=P(A\cup B)-P(A)-P(B) \hspace{.33em}\\~\\ \end{align}}\)
mathmath333
  • mathmath333
i didn't understand
mathmath333
  • mathmath333
Do u mean this \(\large \color{black}{\begin{align} & P(A\cap B)=P(A)\times P(B) \hspace{.33em}\\~\\ \end{align}}\)
ganeshie8
  • ganeshie8
Yes they are independent events, so you simply multiply the probabilities

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