anonymous
  • anonymous
please help... calc will be the death of me lol
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
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anonymous
  • anonymous
@ikram002p heyy any idea here lol
idku
  • idku
this is calculus, are you sure?

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idku
  • idku
|dw:1440615503189:dw|
idku
  • idku
sin(30)=1/2 mutliply both sides times -1 and use the rule -sin(k)=sin(-k)
anonymous
  • anonymous
wait so how did you decide to do sin 30
idku
  • idku
As for your second problem |dw:1440615688714:dw|
idku
  • idku
how you decide to do for sin(30)? what do you want to know?
anonymous
  • anonymous
lets just work on the first one im wayy too lost lol so you drew a reference triangle?
welshfella
  • welshfella
when you have negative values of a trig ratio you might find it easier to remember their signs in the 4 quadrants 0 - 360 degrees
welshfella
  • welshfella
|dw:1440615941625:dw|
dumbcow
  • dumbcow
google unit circle
welshfella
  • welshfella
so they are ALL positive in first quadrant (0 to 90 degrees) Only the sine is positive in 2nd quadrant, only the tangent in the third and only the cosine in the 4th quadrant - otherwise they are negative
anonymous
  • anonymous
okay i get that
welshfella
  • welshfella
so if you have sine x = -0.5 Sine 30 is 0.5 ( thats first quadant) its negative in 2nd and 3rd so 2 values for the angle would be 180-30 = 150 and 180+ 30 = 210 these are the results if the question asks for values of the angle in range 0 to 360 degrees.
welshfella
  • welshfella
oh i messed up there sorry! sine is negative in 3rd and 4th quadrants so thats 210 and 330 dgrees!!
anonymous
  • anonymous
phew i got nervous for a sec i was like wuttt... but i get that so far
welshfella
  • welshfella
|dw:1440616444926:dw|
welshfella
  • welshfella
|dw:1440616515975:dw|
welshfella
  • welshfella
personally i find it easier to use pictures with these problems.
welshfella
  • welshfella
theres 2 triangles worth remembering the one that idku posted and also the 45-45-90 triangle
welshfella
  • welshfella
|dw:1440616730872:dw|
anonymous
  • anonymous
alrigh but for this [prob im dealing with the 30 60 90
welshfella
  • welshfella
2 cos x = sqrt3 cos x = sqrt3/2 so what is the value of angle x ( from the 30 60 90 triangle)?
welshfella
  • welshfella
remember cosine = adjacent / hypotenuse
welshfella
  • welshfella
maybe the presence of the S is confusing you ?
anonymous
  • anonymous
so would i tak inverse cos (sqrt3/2) to find the angle
welshfella
  • welshfella
yes - or you can see it on the diagram |dw:1440617639361:dw|
anonymous
  • anonymous
when i do it the way i said i get a domain error
anonymous
  • anonymous
wait can we stick with #1 for now im trying to understand it
anonymous
  • anonymous
so i get how you found 210 and 330
anonymous
  • anonymous
|dw:1440617866896:dw|
phi
  • phi
when you have time, you might want to review https://www.khanacademy.org/math/trigonometry/unit-circle-trig-func/Trig-unit-circle/v/unit-circle-definition-of-trig-functions-1
anonymous
  • anonymous
ignore that drawing. i just watched a tutorial. so the question is asking me for the angle measure correct?
phi
  • phi
personally I would solve this \[ \sin x = - \frac{1}{2} , \text{ for } 0 \le x \lt 2 \pi\] but graphing (sketching actually) sin x from 0 to 2pi |dw:1440619769364:dw|
phi
  • phi
looking at the curve, it should be clear there are two angles where sin x = -1/2 we should have memorized some "standard angles" in particular sin 30º = 1/2 thus the solutions will be 30º *in the correct quadrants* in particular 180+30 =210 (but put in radians) and 360-30 = 330º, but put in radians.
phi
  • phi
for 2 cos x = sqr(3) \[ \cos x = \frac{\sqrt{3}}{2} \] |dw:1440620036903:dw| again, two solutions we should know cos 30º = sqr(3)/2 thus 30 and 360-30 = 330º
anonymous
  • anonymous
okay i understand much bette. the way i learned from the tutorial is to isolate the x and then look for it on the unit circle to find possible soulutions and then determine the correct quadrants
phi
  • phi
yes, that will work also.
freckles
  • freckles
|dw:1440621102930:dw|

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