The production of water proceeds according to the following equation.
2H2(g) + O2(g) → 2H2O(g)
Which describes a way to speed up the collisions between hydrogen and oxygen molecules to produce more water?
a. Use a less-intense source of heat on the reactants.
b. Maintain the same temperature of the reactants.
c. Place the reactants in a smaller container.
d. Reduce the concentration of the reactants.
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Smaller container means less volume, and the molecules will hit the walls of the container more frequently because there's less space available and the pressure will go up. I guess this would mean that the side with fewer moles would be favored as a result. We count the number of moles on the reactants and products and find that there are fewer moles on the product side, so I guess this would favor the product formation.