Simplify 2 to the 5th over 3 squared all raised to the 4th power.
2 to the 20th over 3 to the 8th
2 to the 9th over 3 to the 8th
8 to the 5th over 12 to the 2nd
2 over 3 to the 2nd

- anonymous

- jamiebookeater

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- anonymous

Please help!!! ;)

- StudyGurl14

\(\Large(\frac{2^5}{3^2})^4\)
First, find 2^5 and 2^2

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## More answers

- StudyGurl14

3^2 I mean

- anonymous

3 x 2?

- anonymous

@StudyGurl14 pls help is it multiplying??

- anonymous

- anonymous

- anonymous

2 times 5 = 10 and 3 times 2 = 6

- tkhunny

\(\left(a^{b}\right)^c = a^{b*c}\)
Do that.

- anonymous

how?

- anonymous

sorry but i dont know how @tkhunny

- anonymous

@StudyGurl14 pls explain

- StudyGurl14

3^2 = 3 x 3

- anonymous

ohh

- anonymous

9

- StudyGurl14

yeah.

- tkhunny

Follow the pattern.
\(\left(\dfrac{2^{5}}{3^{2}}\right)^{4} = \dfrac{\left(2^{5}\right)^{4}}{\left(3^{2}\right)^{4}}\)
I'm pretty sure you can do that. Now the other part.

- anonymous

ok what about the other one?
is it 2 x 6?

- anonymous

studygirl

- anonymous

ugh tkhunny i dont! please its complicated

- tkhunny

You should not ever see a '9' during the course of this problem.

- anonymous

what about 6?

- anonymous

is it 60/40?

- anonymous

like do u multiply 2 and 5 then 3 and 2 and then both by 4?

- anonymous

ok start over. first you multiply what?

- anonymous

- anonymous

- anonymous

is the final answer 0.66 to the 12th?

- tkhunny

Use the rule.
\(\left(a^{b}\right)^{c} = a^{b*c}\) -- That's it. No great complication.
\(\left(2^{5}\right)^{4} = 2^{5*4} = 2^{20}\) -- No more. No less. Done.
You do the denominator.

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