anonymous
  • anonymous
Simplify 2 to the 5th over 3 squared all raised to the 4th power. 2 to the 20th over 3 to the 8th 2 to the 9th over 3 to the 8th 8 to the 5th over 12 to the 2nd 2 over 3 to the 2nd
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Please help!!! ;)
anonymous
  • anonymous
StudyGurl14
  • StudyGurl14
\(\Large(\frac{2^5}{3^2})^4\) First, find 2^5 and 2^2

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StudyGurl14
  • StudyGurl14
3^2 I mean
anonymous
  • anonymous
3 x 2?
anonymous
  • anonymous
@StudyGurl14 pls help is it multiplying??
anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
2 times 5 = 10 and 3 times 2 = 6
tkhunny
  • tkhunny
\(\left(a^{b}\right)^c = a^{b*c}\) Do that.
anonymous
  • anonymous
how?
anonymous
  • anonymous
sorry but i dont know how @tkhunny
anonymous
  • anonymous
@StudyGurl14 pls explain
StudyGurl14
  • StudyGurl14
3^2 = 3 x 3
anonymous
  • anonymous
ohh
anonymous
  • anonymous
9
StudyGurl14
  • StudyGurl14
yeah.
tkhunny
  • tkhunny
Follow the pattern. \(\left(\dfrac{2^{5}}{3^{2}}\right)^{4} = \dfrac{\left(2^{5}\right)^{4}}{\left(3^{2}\right)^{4}}\) I'm pretty sure you can do that. Now the other part.
anonymous
  • anonymous
ok what about the other one? is it 2 x 6?
anonymous
  • anonymous
studygirl
anonymous
  • anonymous
ugh tkhunny i dont! please its complicated
tkhunny
  • tkhunny
You should not ever see a '9' during the course of this problem.
anonymous
  • anonymous
what about 6?
anonymous
  • anonymous
is it 60/40?
anonymous
  • anonymous
like do u multiply 2 and 5 then 3 and 2 and then both by 4?
anonymous
  • anonymous
ok start over. first you multiply what?
anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
is the final answer 0.66 to the 12th?
tkhunny
  • tkhunny
Use the rule. \(\left(a^{b}\right)^{c} = a^{b*c}\) -- That's it. No great complication. \(\left(2^{5}\right)^{4} = 2^{5*4} = 2^{20}\) -- No more. No less. Done. You do the denominator.

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