anonymous one year ago Simplify 2 to the 5th over 3 squared all raised to the 4th power. 2 to the 20th over 3 to the 8th 2 to the 9th over 3 to the 8th 8 to the 5th over 12 to the 2nd 2 over 3 to the 2nd

1. anonymous

2. anonymous

@freckles @phi @perl

3. StudyGurl14

$$\Large(\frac{2^5}{3^2})^4$$ First, find 2^5 and 2^2

4. StudyGurl14

3^2 I mean

5. anonymous

3 x 2?

6. anonymous

@StudyGurl14 pls help is it multiplying??

7. anonymous

@tkhunny

8. anonymous

@perl @triciaal @ganeshie8 @Hero @phi

9. anonymous

2 times 5 = 10 and 3 times 2 = 6

10. tkhunny

$$\left(a^{b}\right)^c = a^{b*c}$$ Do that.

11. anonymous

how?

12. anonymous

sorry but i dont know how @tkhunny

13. anonymous

@StudyGurl14 pls explain

14. StudyGurl14

3^2 = 3 x 3

15. anonymous

ohh

16. anonymous

9

17. StudyGurl14

yeah.

18. tkhunny

Follow the pattern. $$\left(\dfrac{2^{5}}{3^{2}}\right)^{4} = \dfrac{\left(2^{5}\right)^{4}}{\left(3^{2}\right)^{4}}$$ I'm pretty sure you can do that. Now the other part.

19. anonymous

ok what about the other one? is it 2 x 6?

20. anonymous

studygirl

21. anonymous

ugh tkhunny i dont! please its complicated

22. tkhunny

You should not ever see a '9' during the course of this problem.

23. anonymous

24. anonymous

is it 60/40?

25. anonymous

like do u multiply 2 and 5 then 3 and 2 and then both by 4?

26. anonymous

ok start over. first you multiply what?

27. anonymous

@freckles

28. anonymous

@IrishBoy123

29. anonymous

is the final answer 0.66 to the 12th?

30. tkhunny

Use the rule. $$\left(a^{b}\right)^{c} = a^{b*c}$$ -- That's it. No great complication. $$\left(2^{5}\right)^{4} = 2^{5*4} = 2^{20}$$ -- No more. No less. Done. You do the denominator.