AmTran_Bus
  • AmTran_Bus
Help me solve this equation to find state of a hydrogen atom.
Mathematics
katieb
  • katieb
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AmTran_Bus
  • AmTran_Bus
|dw:1440622486752:dw|
AmTran_Bus
  • AmTran_Bus
I keep getting 9.6 but that sure can't be right for hydrogen.
AmTran_Bus
  • AmTran_Bus
I started by distributing the n^2 to the 109680.

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AmTran_Bus
  • AmTran_Bus
I'm sorry, I need to make a correction. It is 97.2 x 10^-7.
perl
  • perl
we are given 1 / ( 97.2 * 10^(-7) ) = 109860( 1 - 1/n^2) divide both sides by 109860 , or multiply both sides by 1/ 109860 which is the same thing 1 / ( 97.2 * 10^(-7) ) * 1 / ( 109860) = 1 - 1/n^2
AmTran_Bus
  • AmTran_Bus
Ok that is .936
AmTran_Bus
  • AmTran_Bus
.936=1-1/n^2
perl
  • perl
.936- 1 = -1/n^2
perl
  • perl
lets add a few more decimals just to be on the safe side with error
perl
  • perl
0.93647058 -1 = -1/n^2 -.0635294 = -1/n^2 multiply both sides by -1 0.0635294 = 1/n^2 multiply both sides by n^2 n^2 * 0.0635294 = 1 divide both sides by 0.0635294 n^2 = 1/ 0.0635294 take square root n = sqrt ( 1 / 0.0635294)
AmTran_Bus
  • AmTran_Bus
Yep. Makes sense to me. I need to compare it to what I did to find my mistake. Thank you.
perl
  • perl
you should get n = 3.96 which is very close to n=4 Your welcome :)
AmTran_Bus
  • AmTran_Bus
That is exactly what I got!
AmTran_Bus
  • AmTran_Bus
|dw:1440624685579:dw| @perl can you help with this one? I'm doing it the same way but getting a negative square root.

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