Identify the axis of symmetry and vertex of f(x) = –2x^2 –2x–1. Axis of symmetry: x = 0.5; Vertex: (0.5, – 0.50) Axis of symmetry: x = – 0.5; Vertex: (– 0.5, 0.50) Axis of symmetry: x = – 0.5; Vertex: (– 0.5, – 0.50) Axis of symmetry: x = 0.5; Vertex: (– 0.5, – 0.50)

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Identify the axis of symmetry and vertex of f(x) = –2x^2 –2x–1. Axis of symmetry: x = 0.5; Vertex: (0.5, – 0.50) Axis of symmetry: x = – 0.5; Vertex: (– 0.5, 0.50) Axis of symmetry: x = – 0.5; Vertex: (– 0.5, – 0.50) Axis of symmetry: x = 0.5; Vertex: (– 0.5, – 0.50)

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

http://www.mathway.com/graph/NTUxODk this is an amazing site for graphing
Do you know how to write in vertex form? If involves completing the square? \[f(x)=-2x^2-2x-1 \\ f(x)=-2(x^2+x)-1 \\ f(x)=-2(x^2+x+L)-1+2L \\ \text{ notice } -2L+2L=0 \\ \text{ we need to figure out what } L \text{ needs to be to } \\ \text{ complete the square inside that one ( )}\]

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

|dw:1440639916432:dw|
vertex form a(x-h)^2 + k = 0 vertex (h, k) axis of symmetry x = h
It's really confusing.
do you know what 's a b and c in the equation ?
No.. I'm really confused with math, I sometimes know things but like need to refresh my mind.. I know some rules in Arabic and some in English.. Because I took math in both languages and now im really really confused
\(\color{blue}{\text{Originally Posted by}}\) @Nnesha or http://openstudy.com/study#/updates/55de281ae4b0f9297e9bc5e7 :=) \(\color{blue}{\text{End of Quote}}\) didn't notice that link doesn't work http://openstudy.com/study#/updates/55daa403e4b0a0d51271c948
ahh i see okay
quadratic equation is \[\huge\rm Ax^2+Bx+C=0\] where a=leading coefficient b=middle term c= constant term
quadratic equation is \[\huge\rm\color{red}{ A}x^2+\color{blue}{B}x+\color{pink}{C} \] where a=leading coefficient b=middle term c= constant term \[\huge\rm \color{Red}{–2}x^2 \color{blue}{–2}x\color{pink}{–1}\] so what is a and b equal to in that equation ?
let me if u didn't understand :=)
not just negative 2 a=-2 b=-2 now use the formula to find x-coordinate of vertex \[\huge\rm \frac{ -b }{ 2a }\] replace b and a with -2
so it would be -2/2^-2?
no \[\frac{ -(-2) }{ 2(-2)}\] don't forget to put the parentheses there is negative sign in the formula and b is also negative and at the denominator it's 2 times -2 not 2 to the -2 power
2(-2) is n't same as 2^(-2)
Ohh okay
now simplify that
it would equal -2?
no
\[\huge\rm \frac{ -(-2) }{ 2(-2)}\] what did you get at the numerator ?
aren't we supposed to divide the numerator and denominator by -2
yes right \[\huge\rm \frac{ -\cancel{(-2)} }{ 2\cancel{(-2)}}\] what would you get at the top ?
the negative sign
0?
no there is one
invisible one :=)
so it should be -1/2
just like 2/2 =1
Oh okay
yes so that's the x-coordinate of the vertex which is also the axis of symmetry
now replace all x for -1/2 into the f(x) function
\[\huge\rm f(-0.5) = –2x^2 –2x–1.\] -1/2 = -0.5 so now replace all x's for -0.5 then solve
f(-0.5) = -2(-0.5)^2-2(0.5)-1
yes right now solve right side :=) to find y-coordinate of the vertex
equals -0.5?
yes right that's y-coordinate of vertex
done!
but the choices have 0.50.. from where did that come from @Nnesha
ohh that's the same .50 or .5
so the answer is C) Axis of symmetry: x = – 0.5; Vertex: (– 0.5, – 0.50)
yep
subtract .50-.5 you will get 0 thats mean both are the same
Oh thank you very much!
my pleasure!

Not the answer you are looking for?

Search for more explanations.

Ask your own question