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anonymous
 one year ago
Identify the axis of symmetry and vertex of f(x) = –2x^2 –2x–1.
Axis of symmetry: x = 0.5; Vertex: (0.5, – 0.50)
Axis of symmetry: x = – 0.5; Vertex: (– 0.5, 0.50)
Axis of symmetry: x = – 0.5; Vertex: (– 0.5, – 0.50)
Axis of symmetry: x = 0.5; Vertex: (– 0.5, – 0.50)
anonymous
 one year ago
Identify the axis of symmetry and vertex of f(x) = –2x^2 –2x–1. Axis of symmetry: x = 0.5; Vertex: (0.5, – 0.50) Axis of symmetry: x = – 0.5; Vertex: (– 0.5, 0.50) Axis of symmetry: x = – 0.5; Vertex: (– 0.5, – 0.50) Axis of symmetry: x = 0.5; Vertex: (– 0.5, – 0.50)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0http://www.mathway.com/graph/NTUxODk this is an amazing site for graphing

freckles
 one year ago
Best ResponseYou've already chosen the best response.0Do you know how to write in vertex form? If involves completing the square? \[f(x)=2x^22x1 \\ f(x)=2(x^2+x)1 \\ f(x)=2(x^2+x+L)1+2L \\ \text{ notice } 2L+2L=0 \\ \text{ we need to figure out what } L \text{ needs to be to } \\ \text{ complete the square inside that one ( )}\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2or http://openstudy.com/study#/updates/55de281ae4b0f9297e9bc5e7 :=)

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440639916432:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0vertex form a(xh)^2 + k = 0 vertex (h, k) axis of symmetry x = h

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It's really confusing.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2do you know what 's a b and c in the equation ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No.. I'm really confused with math, I sometimes know things but like need to refresh my mind.. I know some rules in Arabic and some in English.. Because I took math in both languages and now im really really confused

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\(\color{blue}{\text{Originally Posted by}}\) @Nnesha or http://openstudy.com/study#/updates/55de281ae4b0f9297e9bc5e7 :=) \(\color{blue}{\text{End of Quote}}\) didn't notice that link doesn't work http://openstudy.com/study#/updates/55daa403e4b0a0d51271c948

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2quadratic equation is \[\huge\rm Ax^2+Bx+C=0\] where a=leading coefficient b=middle term c= constant term

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2quadratic equation is \[\huge\rm\color{red}{ A}x^2+\color{blue}{B}x+\color{pink}{C} \] where a=leading coefficient b=middle term c= constant term \[\huge\rm \color{Red}{–2}x^2 \color{blue}{–2}x\color{pink}{–1}\] so what is a and b equal to in that equation ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2let me if u didn't understand :=)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2not just negative 2 a=2 b=2 now use the formula to find xcoordinate of vertex \[\huge\rm \frac{ b }{ 2a }\] replace b and a with 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it would be 2/2^2?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2no \[\frac{ (2) }{ 2(2)}\] don't forget to put the parentheses there is negative sign in the formula and b is also negative and at the denominator it's 2 times 2 not 2 to the 2 power

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.22(2) is n't same as 2^(2)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[\huge\rm \frac{ (2) }{ 2(2)}\] what did you get at the numerator ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0aren't we supposed to divide the numerator and denominator by 2

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yes right \[\huge\rm \frac{ \cancel{(2)} }{ 2\cancel{(2)}}\] what would you get at the top ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yes so that's the xcoordinate of the vertex which is also the axis of symmetry

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2now replace all x for 1/2 into the f(x) function

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[\huge\rm f(0.5) = –2x^2 –2x–1.\] 1/2 = 0.5 so now replace all x's for 0.5 then solve

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0f(0.5) = 2(0.5)^22(0.5)1

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yes right now solve right side :=) to find ycoordinate of the vertex

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yes right that's ycoordinate of vertex

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but the choices have 0.50.. from where did that come from @Nnesha

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2ohh that's the same .50 or .5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the answer is C) Axis of symmetry: x = – 0.5; Vertex: (– 0.5, – 0.50)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2subtract .50.5 you will get 0 thats mean both are the same

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh thank you very much!
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