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http://www.mathway.com/graph/NTUxODk
this is an amazing site for graphing

|dw:1440639916432:dw|

vertex form a(x-h)^2 + k = 0
vertex (h, k)
axis of symmetry x = h

It's really confusing.

do you know what 's a b and c in the equation ?

ahh i see okay

let me if u didn't understand :=)

so it would be -2/2^-2?

2(-2) is n't same as 2^(-2)

Ohh okay

now simplify that

it would equal -2?

no

\[\huge\rm \frac{ -(-2) }{ 2(-2)}\]
what did you get at the numerator ?

aren't we supposed to divide the numerator and denominator by -2

yes right \[\huge\rm \frac{ -\cancel{(-2)} }{ 2\cancel{(-2)}}\]
what would you get at the top ?

the negative sign

0?

no there is one

invisible one :=)

so it should be -1/2

just like 2/2 =1

Oh okay

yes so that's the x-coordinate of the vertex which is also the axis of symmetry

now replace all x for -1/2 into the f(x) function

\[\huge\rm f(-0.5) = –2x^2 –2x–1.\] -1/2 = -0.5
so now replace all x's for -0.5 then solve

f(-0.5) = -2(-0.5)^2-2(0.5)-1

yes right now solve right side :=) to find y-coordinate of the vertex

equals -0.5?

yes right that's y-coordinate of vertex

done!

ohh that's the same .50 or .5

so the answer is C) Axis of symmetry: x = – 0.5; Vertex: (– 0.5, – 0.50)

yep

subtract .50-.5 you will get 0 thats mean both are the same

Oh thank you very much!

my pleasure!