anonymous
  • anonymous
Identify the axis of symmetry and vertex of f(x) = –2x^2 –2x–1. Axis of symmetry: x = 0.5; Vertex: (0.5, – 0.50) Axis of symmetry: x = – 0.5; Vertex: (– 0.5, 0.50) Axis of symmetry: x = – 0.5; Vertex: (– 0.5, – 0.50) Axis of symmetry: x = 0.5; Vertex: (– 0.5, – 0.50)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@fashionismybesty
anonymous
  • anonymous
http://www.mathway.com/graph/NTUxODk this is an amazing site for graphing
freckles
  • freckles
Do you know how to write in vertex form? If involves completing the square? \[f(x)=-2x^2-2x-1 \\ f(x)=-2(x^2+x)-1 \\ f(x)=-2(x^2+x+L)-1+2L \\ \text{ notice } -2L+2L=0 \\ \text{ we need to figure out what } L \text{ needs to be to } \\ \text{ complete the square inside that one ( )}\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

triciaal
  • triciaal
|dw:1440639916432:dw|
triciaal
  • triciaal
vertex form a(x-h)^2 + k = 0 vertex (h, k) axis of symmetry x = h
anonymous
  • anonymous
It's really confusing.
Nnesha
  • Nnesha
do you know what 's a b and c in the equation ?
anonymous
  • anonymous
No.. I'm really confused with math, I sometimes know things but like need to refresh my mind.. I know some rules in Arabic and some in English.. Because I took math in both languages and now im really really confused
Nnesha
  • Nnesha
\(\color{blue}{\text{Originally Posted by}}\) @Nnesha or http://openstudy.com/study#/updates/55de281ae4b0f9297e9bc5e7 :=) \(\color{blue}{\text{End of Quote}}\) didn't notice that link doesn't work http://openstudy.com/study#/updates/55daa403e4b0a0d51271c948
Nnesha
  • Nnesha
ahh i see okay
Nnesha
  • Nnesha
quadratic equation is \[\huge\rm Ax^2+Bx+C=0\] where a=leading coefficient b=middle term c= constant term
Nnesha
  • Nnesha
quadratic equation is \[\huge\rm\color{red}{ A}x^2+\color{blue}{B}x+\color{pink}{C} \] where a=leading coefficient b=middle term c= constant term \[\huge\rm \color{Red}{–2}x^2 \color{blue}{–2}x\color{pink}{–1}\] so what is a and b equal to in that equation ?
Nnesha
  • Nnesha
let me if u didn't understand :=)
anonymous
  • anonymous
2? @Nnesha
Nnesha
  • Nnesha
not just negative 2 a=-2 b=-2 now use the formula to find x-coordinate of vertex \[\huge\rm \frac{ -b }{ 2a }\] replace b and a with -2
anonymous
  • anonymous
so it would be -2/2^-2?
Nnesha
  • Nnesha
no \[\frac{ -(-2) }{ 2(-2)}\] don't forget to put the parentheses there is negative sign in the formula and b is also negative and at the denominator it's 2 times -2 not 2 to the -2 power
Nnesha
  • Nnesha
2(-2) is n't same as 2^(-2)
anonymous
  • anonymous
Ohh okay
Nnesha
  • Nnesha
now simplify that
anonymous
  • anonymous
it would equal -2?
Nnesha
  • Nnesha
no
Nnesha
  • Nnesha
\[\huge\rm \frac{ -(-2) }{ 2(-2)}\] what did you get at the numerator ?
anonymous
  • anonymous
aren't we supposed to divide the numerator and denominator by -2
Nnesha
  • Nnesha
yes right \[\huge\rm \frac{ -\cancel{(-2)} }{ 2\cancel{(-2)}}\] what would you get at the top ?
anonymous
  • anonymous
the negative sign
anonymous
  • anonymous
0?
Nnesha
  • Nnesha
no there is one
Nnesha
  • Nnesha
invisible one :=)
Nnesha
  • Nnesha
so it should be -1/2
Nnesha
  • Nnesha
just like 2/2 =1
anonymous
  • anonymous
Oh okay
Nnesha
  • Nnesha
yes so that's the x-coordinate of the vertex which is also the axis of symmetry
Nnesha
  • Nnesha
now replace all x for -1/2 into the f(x) function
Nnesha
  • Nnesha
\[\huge\rm f(-0.5) = –2x^2 –2x–1.\] -1/2 = -0.5 so now replace all x's for -0.5 then solve
anonymous
  • anonymous
f(-0.5) = -2(-0.5)^2-2(0.5)-1
Nnesha
  • Nnesha
yes right now solve right side :=) to find y-coordinate of the vertex
anonymous
  • anonymous
equals -0.5?
Nnesha
  • Nnesha
yes right that's y-coordinate of vertex
Nnesha
  • Nnesha
done!
anonymous
  • anonymous
but the choices have 0.50.. from where did that come from @Nnesha
Nnesha
  • Nnesha
ohh that's the same .50 or .5
anonymous
  • anonymous
so the answer is C) Axis of symmetry: x = – 0.5; Vertex: (– 0.5, – 0.50)
Nnesha
  • Nnesha
yep
Nnesha
  • Nnesha
subtract .50-.5 you will get 0 thats mean both are the same
anonymous
  • anonymous
Oh thank you very much!
Nnesha
  • Nnesha
my pleasure!

Looking for something else?

Not the answer you are looking for? Search for more explanations.