Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

Looking for something else?

Not the answer you are looking for? Search for more explanations.

- anonymous

Would someone like to help me with intercepts for a medal?
I'll post the problem below...

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions.

Get your **free** account and access **expert** answers to this and **thousands** of other questions

- anonymous

Would someone like to help me with intercepts for a medal?
I'll post the problem below...

- chestercat

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

\[x^2y-x^2+4y=0\]
I need to find the x and y intercepts of this problem, but I'm not sure how to.
I've tried replacing each variable with 0 to solve for the other variable, but I keep getting strange answers...

- dessyj1

Can you show me what you got when you tried to find the x-intercept?

- anonymous

I just got 0

Looking for something else?

Not the answer you are looking for? Search for more explanations.

- anonymous

\[x^2y−x^2+4y=0\]
I factored the equation...
\[x^2(y-1)+4y=0\]
then I replaced y with 0...
\[x^2((0)-1)+4(0)=0\]
solved it...
\[x^2=0\]
and squared...
\[x=0\]

- dessyj1

Why do you think that is weird?
Because that is the answer.

- dessyj1

Also, you cannot factor that equation

- dessyj1

actually, you just factored the first two terms so that's okay.

- anonymous

I just wasn't sure about the answer since I originally got a different answer and didn't know which was correct.
Thanks for clarifying though. :)

- anonymous

By the way, you wouldn't happen to know anything about the symmetry of a function would you?

- dessyj1

When y=0, x=0. It is a point on the origin. (0,0)

- dessyj1

So, the x-int is 0 and a y-int is 0

- anonymous

Yes

- anonymous

I graphed the function earlier and that's what it showed as well

- dessyj1

I do not know anything about the symmetry of a function. That is another question you will have to ask.

Looking for something else?

Not the answer you are looking for? Search for more explanations.