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anonymous

  • one year ago

How do I find Y for ax+by+c=0

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  1. anonymous
    • one year ago
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    By Y you mean y right?

  2. anonymous
    • one year ago
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    Yes

  3. anonymous
    • one year ago
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    Then, to express y in terms of everything else, we have to isolate it on one side of the equal sign while having everything else on the other side of the equal sign. To do this, we use the algebraic operations of adding, subtracting, and dividing to solve for y. It can start like this.\[ax+by+c = 0 \implies ax + by + c +(-c) = -c\].

  4. anonymous
    • one year ago
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    Since\[c + (-c) = 0 \implies ax + by = -c\]

  5. anonymous
    • one year ago
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    Now, we can do the same thing for ax.\[(-ax)+ax + by = -(ax) - c \ \implies by = -ax -c\]

  6. anonymous
    • one year ago
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    Now provided that \[b \neq 0 \], then \[\frac{ by }{ b } = \frac{ -ax -c }{ b } \ \implies y = \frac{ -ax }{ b } - \frac{ c }{ b }\]

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