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## anonymous one year ago How do I find Y for ax+by+c=0

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1. anonymous

By Y you mean y right?

2. anonymous

Yes

3. anonymous

Then, to express y in terms of everything else, we have to isolate it on one side of the equal sign while having everything else on the other side of the equal sign. To do this, we use the algebraic operations of adding, subtracting, and dividing to solve for y. It can start like this.$ax+by+c = 0 \implies ax + by + c +(-c) = -c$.

4. anonymous

Since$c + (-c) = 0 \implies ax + by = -c$

5. anonymous

Now, we can do the same thing for ax.$(-ax)+ax + by = -(ax) - c \ \implies by = -ax -c$

6. anonymous

Now provided that $b \neq 0$, then $\frac{ by }{ b } = \frac{ -ax -c }{ b } \ \implies y = \frac{ -ax }{ b } - \frac{ c }{ b }$

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