## BioHazard9064 one year ago Algebra Help

1. BioHazard9064

Is the simplified form of $2\sqrt{3}* 2\sqrt{6}$ rational?

2. anonymous

Do you have an idea on what to do and are just unsure?

3. BioHazard9064

Answers: A. Yes B. No

4. BioHazard9064

No I don't really know

5. anonymous

Ok, you can think about multiplying the numbers in front of the radical signs and the numbers under the radical signs separately.

6. BioHazard9064

ok so 2*2 is 4

7. anonymous

Yes, and what is 3 * 6?

8. BioHazard9064

18

9. anonymous

Ok so we have$(2 \sqrt3 )(2\sqrt6) = 4\sqrt{18}$

10. BioHazard9064

so is that rational ?

11. anonymous

There is a 3^2 underneath the radical so you can pull that out$4\sqrt{18} = 12\sqrt{2}$

12. anonymous

12 may be rational, but the sqrt 2 is not, so their product isn't rational either.

13. BioHazard9064

So its B

14. anonymous

Yes, it isn't rational

15. BioHazard9064

so lets say though its like this $2\sqrt{3}-2\sqrt{3}$ is that rational?

16. BioHazard9064

I think not?

17. anonymous

Well is zero rational? What does it mean to be rational anyways? To be rational means that a number can be represented as some fraction with either the numerator or denominator being odd.

18. BioHazard9064

and you cant really have 0 in a fraction

19. anonymous

Well we can right? I can put $2\sqrt3 - 2\sqrt3 = 0 = \dfrac{0}{1}$

20. BioHazard9064

oh ok I see that now so it would be rational

21. anonymous

Yes

22. BioHazard9064

ok thanks allot

23. anonymous

No problem, good luck in your studies.

24. BioHazard9064

thanks I need it xD