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BioHazard9064

  • one year ago

Algebra Help

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  1. BioHazard9064
    • one year ago
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    Is the simplified form of \[2\sqrt{3}* 2\sqrt{6}\] rational?

  2. anonymous
    • one year ago
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    Do you have an idea on what to do and are just unsure?

  3. BioHazard9064
    • one year ago
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    Answers: A. Yes B. No

  4. BioHazard9064
    • one year ago
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    No I don't really know

  5. anonymous
    • one year ago
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    Ok, you can think about multiplying the numbers in front of the radical signs and the numbers under the radical signs separately.

  6. BioHazard9064
    • one year ago
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    ok so 2*2 is 4

  7. anonymous
    • one year ago
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    Yes, and what is 3 * 6?

  8. BioHazard9064
    • one year ago
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    18

  9. anonymous
    • one year ago
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    Ok so we have\[(2 \sqrt3 )(2\sqrt6) = 4\sqrt{18}\]

  10. BioHazard9064
    • one year ago
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    so is that rational ?

  11. anonymous
    • one year ago
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    There is a 3^2 underneath the radical so you can pull that out\[4\sqrt{18} = 12\sqrt{2}\]

  12. anonymous
    • one year ago
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    12 may be rational, but the sqrt 2 is not, so their product isn't rational either.

  13. BioHazard9064
    • one year ago
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    So its B

  14. anonymous
    • one year ago
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    Yes, it isn't rational

  15. BioHazard9064
    • one year ago
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    so lets say though its like this \[2\sqrt{3}-2\sqrt{3}\] is that rational?

  16. BioHazard9064
    • one year ago
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    I think not?

  17. anonymous
    • one year ago
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    Well is zero rational? What does it mean to be rational anyways? To be rational means that a number can be represented as some fraction with either the numerator or denominator being odd.

  18. BioHazard9064
    • one year ago
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    and you cant really have 0 in a fraction

  19. anonymous
    • one year ago
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    Well we can right? I can put \[2\sqrt3 - 2\sqrt3 = 0 = \dfrac{0}{1}\]

  20. BioHazard9064
    • one year ago
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    oh ok I see that now so it would be rational

  21. anonymous
    • one year ago
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    Yes

  22. BioHazard9064
    • one year ago
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    ok thanks allot

  23. anonymous
    • one year ago
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    No problem, good luck in your studies.

  24. BioHazard9064
    • one year ago
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    thanks I need it xD

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