anonymous
  • anonymous
Quadrilateral OPQR is inscribed inside a circle as shown below. What equation would be needed to solve for angle R? What is the measure of angle R? You must show all work and calculations to receive credit.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
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anonymous
  • anonymous
@Hero @jim_thompson5910 @perl
jim_thompson5910
  • jim_thompson5910
hint: with any inscribed quadrilateral in a circle, the opposite angles always add to 180 degrees that means angle R + angle P = 180 (3y+8) + (y) = 180

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More answers

anonymous
  • anonymous
Okay, i see that but i don't quite understand what to do cause im really confused on how to do this :/
jim_thompson5910
  • jim_thompson5910
you just have to solve 3y+8+y = 180 for y
jim_thompson5910
  • jim_thompson5910
3y+8+y = 180 4y+8 = 180 ... Combine like terms. 4y+8-8 = 180-8 ... Subtract 8 from both sides. 4y+0 = 172 4y = 172 ... ... ... y = ???
anonymous
  • anonymous
43?
jim_thompson5910
  • jim_thompson5910
yep
anonymous
  • anonymous
Yayy we got one(: now can you help me finish it ?
anonymous
  • anonymous
@jim_thompson5910 or are we done with the problem ?
jim_thompson5910
  • jim_thompson5910
now that you know the value of y, use it to compute angle R
anonymous
  • anonymous
How do i do that .. i dont know how . Can you help me work through it ?
jim_thompson5910
  • jim_thompson5910
what expression is shown for angle R
anonymous
  • anonymous
the (3y +8) ?
jim_thompson5910
  • jim_thompson5910
plug y = 43 into that and evaluate
anonymous
  • anonymous
So (3 * 43 +8)?
jim_thompson5910
  • jim_thompson5910
yes evaluate that
anonymous
  • anonymous
54?
jim_thompson5910
  • jim_thompson5910
no
jim_thompson5910
  • jim_thompson5910
that's too small
anonymous
  • anonymous
then im confused , once i do the (3*43+8) .. im lost what to do
jim_thompson5910
  • jim_thompson5910
how did you get 54 ?
anonymous
  • anonymous
Oh i missed calculated i meant the answer would be 137?
jim_thompson5910
  • jim_thompson5910
yes 137 is your answer
anonymous
  • anonymous
Thank you!! So are we done with this question then ?
jim_thompson5910
  • jim_thompson5910
yes
anonymous
  • anonymous
Thank you soo much for your help!!
jim_thompson5910
  • jim_thompson5910
you're welcome

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